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kvv77 [185]
3 years ago
12

The net of a right rectangular prism is shown below: Find the surface area of the prism with the given net (in square inches).

Mathematics
2 answers:
Leto [7]3 years ago
5 0

Answer:

248

Step-by-step explanation:

Katen [24]3 years ago
4 0
248

God bless u. I tried my best
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The temperature at 10 AM is 12°F. The temperature at 6 AM was -7°F. How many degrees did the temperature rise?
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Answer:

19 degrees more

Step-by-step explanation:

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3 years ago
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Every 6th voter gets a button. Every 7th voter gets a sticker. Which voter is the first to receive both items?
MrMuchimi

Answer:

42

Step-by-step explanation:

Use LCM of 6 and 7 to find a number that is the same:

6     12     18     24     30     36     42

7     14     21     28     35     42

Since 42 shows up in both, the 42th voter gets a button and sticker.

Hope this helped.

8 0
2 years ago
Your school football team has 10 scheduled games for the season. You want to attend at least 4 games. How many different combina
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24 combinations i believe

8 0
3 years ago
There are 23 textbooks on the shelf in ms. McDonald's class. Each cover is 13 inches long and 5 inches wide ? What is the combin
MariettaO [177]
Wait for area, wouldn't you just times 13 and 5 and get 65 and then times 23?
5 0
3 years ago
Solve the system of equations by graphing. x+y=-9 4x+y=-19
shutvik [7]

For this case we have the following system of equations:

x + y = -9\\4x + y = -19

We multiply the first equation by -4:

-4x-4y = 36

We have the following equivalent system of equations:

-4x-4y = 36\\4x + y = -19

We add the equations:

-4x + 4x-4y + y = 36-19\\-3y = 17\\y = - \frac {17} {3}

We find the value of the variable "x":

x = -9-yx = -9 - (- \frac {17} {3})\\x = -9 + \frac {17} {3}\\x = \frac {-27 + 17} {3}\\x = - \frac {10} {3}

Thus, the solution of the system is:

(x, y): (- \frac {10} {3}, - \frac {17} {3})

See the graphic in the attached image

ANswer:

(x, y): (- \frac {10} {3}, - \frac {17} {3})

See the graphic in the attached image

4 0
3 years ago
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