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kvv77 [185]
3 years ago
12

The net of a right rectangular prism is shown below: Find the surface area of the prism with the given net (in square inches).

Mathematics
2 answers:
Leto [7]3 years ago
5 0

Answer:

248

Step-by-step explanation:

Katen [24]3 years ago
4 0
248

God bless u. I tried my best
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Sarah's hair appointment is 30 miles away. How fast must she travel to get there in 60 minutes?
Fudgin [204]

Answer:

30 miles an hour

Step-by-step explanation:

6 0
3 years ago
Write a numerator that makes the statement true. 1/2 < /10 < 4/5
juin [17]

Answer:

10/5

Step-by-step explanation:

Because 10 is half of 5 and they are asking what will make this statement true 1/2 is half too

3 0
3 years ago
Read 2 more answers
If P is the incenter of triangle JKL, find the measure of JKP.
ladessa [460]

Answer:

m∠JKP = 31.5°

Step-by-step explanation:

Incenter of a triangle is the point where all the bisectors of interior angles intersect each other.

JN is the angle bisector of ∠KJL.

Therefore, m∠KJN = m∠LJN

(7x - 6) = (5x + 4)

7x - 5x = 6 + 4

2x = 10

x = 5

m∠KJN = (7x - 6)

            = 7(5) - 6

            = 35 - 6

            = 29°

In ΔKJN,

m∠JKN + m∠KNJ + m∠NJK = 180°

m∠JKN + 90° + 29° = 180°

m∠JKN = 180°- 119° = 61°

Since KO is the angle bisector of ∠JKN,

m∠JKP = \frac{1}{2}(\angle JKN)

            = \frac{1}{2}(61)

            = 30.5°

6 0
3 years ago
Graph the image of square CDEF after a reflection across the x-axis​
Rina8888 [55]

Answer:

If you have a general point (x, y), and you reflect it across the x-axis, the coordinates of the new point will be:

(x,-y)

So we only change the sign of the y-component.

Now, if we do a reflection across the x-axis of a whole figure, then we apply the reflection to all the points that make the figure.

Then, we could just apply the reflection to the vertices of the square, then graph the new vertices, and then connect them, that is equivalent to graph the image of the square after the reflection.

The original vertices are:

C = (-3, 7)

D = (0, 7)

E = (0, 10)

F = (-3, 10)

Now we apply the reflection, remember that this only changes the sign of the y-component, then the new vertices are:

C' = (-3, -7)

D' = (0, -7)

E' = (0, - 10)

F' = (0, - 10)

Now we need to graph these points and connect them to get the reflected figure, the image can be seen below.

5 0
2 years ago
The product of two numbers is 21. If the first number is -3 which equation respents this situation and what is the second number
Vaselesa [24]

Let the second no. be x

-3x = 21 → x = 21/-3 → x = -7

4 0
1 year ago
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