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alexdok [17]
3 years ago
10

M is at least 25 m_____25 options >

Mathematics
2 answers:
bogdanovich [222]3 years ago
8 0
M is greater than or equal to 25
Remember to put a line underneath > <---- This
damaskus [11]3 years ago
7 0
M > 25
_

Make sure u put the line underneath > because m could equal 25
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Change 1/4 to a decimal, then a percent. 0.25, 2.5% 2.5, 25% 0.25, 0.25% 0.25, 25%
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1/4 to a decimal 0.25
to a percent is 25%
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3 years ago
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Add the following values.<br> (2.1 × 1016) + (3.2 × 1015)
qwelly [4]

Answer:

5381.6

Step-by-step explanation:

(2.1 × 1016) + (3.2 × 1015)

= 5381.6

8 0
2 years ago
Philip's family traveled 3/10 of the distance to his grandmother's house on saturday. They traveled 4/7 of the remaining distanc
Nataly [62]
Okay do 4*10 and 7*10 (you get 40/70) and then do 3*7 and 10*7 (so now you've got 21/70) then add 21/70+40/70 and that's the total distance
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3 years ago
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The expression 2.5a+2b gives the cost (in dollars) for a DVDs and b CDs at a moving sale. a. The cost for 1 DVD is $ and the cos
Mekhanik [1.2K]

Answer/Step-by-step Explanation:

Given:

a = no. of DVDs

b = no. of CDs

Total cost ($) for DVDs and CDs = 2.5a + 2b

a. The cost for 1 DVD = 2.5(a) = 2.5(1) = $2.5

The cost for 1 CD = 2(b) = 2(1) = $2

b. Total cost for 4 DVDs and 4 CDs:

Substitute a = 4, and b = 4 into the equation.

2.5(4) + 2(4)

10 + 8 = 18

Total cost for 4 DVDs and 4 CDs = $18

c. To find out if $20 would be enough to buy 6 DVDs and 3 CDs, substitute a = 6, and b = 3 into the equation. Solve for the total cost to see if it equals $20 or is less than $20. If it's greater than $20, then it won't be enough.

2.5(6) + 2(3)

15 + 6 = 21

6 DVDs and 3 CDs cost more than $20, therefore, $20 is not enough.

5 0
3 years ago
- Given a test statistic of t= 3.018 of a left-tailed test with n= 13, use a 0.01 significance level
alina1380 [7]

Using the t-distribution, it is found that the correct option is:

0.005 < P-value < 0.01, reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the mean of a given population is equal to 85, that is:

H_0: \mu = 85

We have a left-tailed test, hence, at the alternative hypothesis, it is tested if the mean of the population is less than 85, that is:

H_1: \mu < 85

<h3>What is the decision?</h3>

The test statistic is of t = -3.018.

Using a t-distribution calculator, with test statistic t = -3.018, 13 - 1 = 12 df and a significance level of 0.01, it is found that the p-value for a left-tailed test is of 0.0051.

The p-value is <u>less than 0.01</u>, hence the null hypothesis is rejected and the correct option is:

0.005 < P-value < 0.01, reject the null hypothesis.

More can be learned about the t-distribution at brainly.com/question/16313918

5 0
2 years ago
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