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Delicious77 [7]
3 years ago
5

Someone, please solve this, TYSM!

Mathematics
1 answer:
Tanzania [10]3 years ago
5 0
1, 5, 10, 10, 5, 1. I hope this helps!
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Lamont Gatling purchased a phone answering system for his home office. The list price was $99.86. He also purchased a 12-foot ha
Natali5045456 [20]

Answer:

$130.7086

Step-by-step explanation:

List price of phone answering system = $99.86

Handset cord = $8.95

Telephone wire = 45 cent/foot ; length = 50 feet

Rebate on phone system = $5

Store coupon =$1 of each accessory

Sales tax = 6% on final price

Price before coupon = (99.86 + 8.95 + (50*0.45)) =$131. 31

Number of accessories = 3

Total coupon = $5 + ($1 * 3) = $8

Price after coupon = final price : $131.31 - $8 = $123.31

Sales tax = 0.06 * $123.31 = $7.3986

Amount paid = $123.31 + $7.3986 = $130.7086

4 0
3 years ago
If sin theta = 2/3, which of the following are possible
Ira Lisetskai [31]
Sin ø = opposite/hypotenuse = 2/3, cos ø = adjacent/hypotenuse = ?/3, tan ø = opposite/adjacent = 2/?, sec ø = 1/cos ø

to solve ?, Pythagorean theorem must be applied
hypotenuse^2 = adjacent^2 + opposite^2

Manipulating the equation to find the adjacent value = ?

adjacent = sqrt(hypotenuse^2 - opposite^2) = sqrt(9-4)
adjacent = sqrt(5)

so cos ø = sqrt(5)/3, tan ø = 2/sqrt(5) and sec <span>ø = 3/sqrt(5) since the value is positive the possible equivalent trigonometric function should be positive, the answer should be b </span>

3 0
3 years ago
Read 2 more answers
NEED HELP ASAP WILL GIVE BRAINLIEST
AleksandrR [38]
I must assume that your graph is that of a straight line, and that the end points of the line are P and B, and (finally) that T is between P and B.  If these assumptions are correct, then the length of the line segment PB connecting points P and B is 15 + 10, or 25.
5 0
4 years ago
1)
Artist 52 [7]
The vertex of the quadratic function is: A) (0,2)
8 0
3 years ago
Find the Interest Earned.
Alex787 [66]
A=p(1+i/m)^mn
Interest earned
I=A-p

A=980×(1+0.08÷4)^(4×5)
A=1,456.23

I=1,456.23−980
I=476.23

A=7,200×(1+0.04)^(8)
A=9,853.69

I=9,853.69−7,200
I=2,653.69

A=15,520×(1+0.06÷2)^(2×4)
A=19,660.27

I=19,660.27−15,520
I=4,140.27
5 0
4 years ago
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