Answer with explanation:
Given:
In Δ DEF, ∠3=∠4.
To prove:→ DE=E F
Proof:
1. ∠3=∠4------[Given]
2. →∠1 and ∠ 3 are Supplementary to each other.
(a)⇒∠1 + ∠ 3=180°
→∠2 and ∠ 4 are also Supplementary to each other.
(b)⇒∠2 + ∠ 4=180°
--------------------[Exterior sides in opposite rays]
3. From 1 , a and b
⇒∠ 1 = ∠ 2-------[Two Angles Supplementary to equal Angles are equal to each other]
4. 
If two angles of a Triangle are equal , then side opposite to these angles are equal.
The measure of the missing side is 3x^3 +2x - 7y + 9
<h3>Perimeter of a triangle</h3>
The perimeter of a triangle is equal to the sum of all the sides of the triangle. Mathematically;
P = s1 + s2 + s3
where;
s1 = s2 = -8x^3 + 2
P = -13x^3 + 2x - 7y + 3
Substitute the given parameters
-13x^3 + 2x - 7y + 3 = s3. + 2(-8x^3 + 2)
-13x^3 + 2x - 7y + 3 = s3 - 16x^3 -4
s3 = -13x^3 + 2x - 7y + 3 + 16x^3 + 6
s3 = 3x^3 +2x - 7y + 9
Hence the measure of the missing side is 3x^3 +2x - 7y + 9
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Answer:
x=9 and the missing angle is 44
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Answer:
Period =½
Equation of midline, y=0
Maximum =2
Minimum=-2
Step-by-step explanation:
The given function is
The period is given by:
The equation of the midline is y=0 since there is no vertical shift
The amplitude of this function is 2 so the range is -2≤y≤2.
Hence the maximum value is 2 and minimum value is -2
