Answer: 353.6 g.
Explanation:
1) Word equation (given)
Sodium phosphate + calcium choride → sodium chloride + calcium phosphate
2) Balanced chemical equation
2 Na₃PO₄ +3 CaCl₂ → 6 NaCl + Ca₃(PO4)₂
3) Mole ratio
2 moles Na₃PO₄ : 3 moles CaCl₂ : 6 moles NaCl : 1 mole Ca₃(PO4)₂
4) Formula to convert grams to moles
number of moles = mass in grams / molar mass
5) Number of moles of limiting reactant
a) mass in grams = 379.4 g CaCl₂
b) molar mass CaCl₂ = 110.98 g/mol
c) number of moles CaCl₂ = 379.4 g / 110.98 g/mol = 3.419 moles
6) Theoretical yield of Ca₃(PO4)₂
3 moles CaCl₂ / 1 mole Ca₃(PO4)₂ = 3.419 moles CaCl₂ / x ⇒
x = 3.419 × 1 / 3 = 1.140 moles Ca₃(PO4)₂
7) Convert 1.140 moles Ca₃(PO4)₂
a) molar mass Ca₃(PO4)₂ = 310.1767 g/mol
b) mass in grams = number of moles × molar mass = 1.140 moles × 310.1767 g/mol = 353.6 g ← answer.
