<u>Answer:</u>
<u>For a:</u> The isotopic symbol of the above atom will be 
<u>For b:</u> The isotopic symbol of the above atom will be 
<u>For c:</u> the isotopic symbol of the above atom will be 
<u>Explanation:</u>
The isotopic representation of an atom is: 
where,
Z = Atomic number of the atom
A = Mass number of the atom
X = Symbol of the atom
Atomic number of iodine = 53
Mass number of iodine = 131
Symbol of iodine = I
The isotopic symbol of the above atom will be 
- <u>For b:</u> Iridium-192
Atomic number of iridium = 77
Mass number of iridium = 192
Symbol of iridium = Ir
The isotopic symbol of the above atom will be 
- <u>For c:</u> Samarium-153
Atomic number of samarium = 62
Mass number of samarium = 153
Symbol of samarium = Sm
The isotopic symbol of the above atom will be 
Answer:
B or C
Explanation:
I don't really know sorry.
Answer:
a) H3PO4 (aq) + 3 KOH (aq) → K3PO4 (aq) + 3 H2O (l)
b)
AgNO3 (aq) + NaCl (aq) → AgCl (s) + NaNO3 (aq)
c)
Ca(OH)2 (s) + 2 H3PO4 (aq) → Ca(H2PO4)2 (s) + 2 H2O (l)
d)
2 KI (aq) + Pb(NO3)2 (aq) → 2 KNO3 (aq) + PbI2 (s)
e)
3 H2SO4 (aq) + 2 Al(OH)3 (s) → 6 H2O (l) + Al2(SO4)3 (aq)
All balanced equation for each reaction!!
Hmm. This is very unspecific but it could either be indicating the pH of the solution or just saying it is an aqeous solution.