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ehidna [41]
3 years ago
10

A basketball coach asks half his players to stretch before each game; the other players do not stretch. After a month of games,

she analyzes their playing stats. She concludes the stretching helped improve their performance on the court. How can the coach test the means to be sure the results not likely to happen by chance?
a. She can pick players at random and analyze their playing stats without calculating means.
b. She can analyze the two groups by calculating the means and the difference of the means.
c. She can rerandomize the results by separating the two groups randomly, then calculate the means and the difference of the means.
d. She can pick the players she wants to analyze based on the best stats.
Mathematics
2 answers:
Nonamiya [84]3 years ago
8 0
The correct answer is C. Randomizing the groups and calculating the means and difference of the means.
Solnce55 [7]3 years ago
3 0
The correct answer is C
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Snowcat [4.5K]

Answer:

Speed = \frac{38}{3}km/hr

Step-by-step explanation:

Given

Distance = 3\frac{1}{6}km

Time = \frac{1}{4}hr

Required

Determine the average speed

Average speed is calculated as thus;

Speed = \frac{Distance}{Time}

Speed = 3\frac{1}{6}/\frac{1}{4}

Speed = 3\frac{1}{6} * \frac{4}{1}

Convert Mixed Fraction to Improper fraction

Speed = \frac{19}{6} * \frac{4}{1}

Speed = \frac{19 * 4}{6 * 1}

Speed = \frac{76}{6}

Divide both sides of the fraction by 2

Speed = \frac{38}{3}

Hence:

The speed is:

Speed = \frac{38}{3}km/hr

3 0
3 years ago
omg hey, so im doing my maths homework and there are 7 numbers. 3 9 3 5 7 6 1... 3 of these numbers have a mean of 6. which ones
Debora [2.8K]

Answer:

3, 6, 9

Step-by-step explanation:

Add them together 3 + 6 + 9 = 18

Divide by 3

4 0
2 years ago
Ill give brainliest please help with this algebra!!
creativ13 [48]

Answer:

Each of these equations solves as 1, because each one of them is an instance of the same expression being divided by itself.

This will <em>always</em> give you a value of 1, as long as the denominator does not end up with a zero value.

Take for instance the third question:

\frac{p^4}{p^4}\\= p^4 \times p^{-4}\\= p^{(4 - 4)}\\= p^0\\= 1

This stands true with all three questions.

HOWEVER

I say this assuming that the 5 following the first brackets in the first question is meant to be an exponent, and not a multiple.  Given that the norm is to make any numeric multiples precede the brackets, I assume it is an exponent. and we're good.

It's not using superscript though, which could mean that they want it multiplied by five instead of raised to the power of.

If that's case, we can solve it the same way we solved question 20.  If the bases are the same, then when multiplying or dividing the terms, you can simply add or subtract the exponents respectively:

\frac{(4x + 2y)\times5}{(4x + 2y)^5}\\= 5(4x + 2y) \times (4x + 2y)^{-5}\\= 5(4x + 2y)^1 \times (4x + 2y)^{-5}\\= 5(4x + 2y)^{1 - 5}\\= 5(4x + 2y)^{-4}\\= \frac{5}{(4x + 2y)^{4}}

Again, this is probably not the correct answer for question 18, as that 5 is almost guaranteed to be meant as an exponent.  If it is instead a coefficient though, then this would be the answer to it.

8 0
3 years ago
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IgorLugansk [536]

Answer:

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Step-by-step explanation:

Its right.

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4 years ago
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