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Hitman42 [59]
2 years ago
15

What is the solution of this system of linear equations? 3y = x + 6 y – x = 3

Mathematics
1 answer:
Fofino [41]2 years ago
5 0
First isolate y by adding x to both sides in y-x=3 and getting y=x+3
Step 1: substitute x+3 for y in 3y=x+6 to get 3(x+3)=x+6
Step 2: distribute 3x+9=x+6
Step 3: subtract like terms 2x=-3
Step 4: divide x=-3/2

substitute -3/2 for x in y=x+3 to get
y=-3/2+3
y=3/2

answer: y=3/2 x=-3/2
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Answer:

slope= 0

Step-by-step explanation:

slope (m)= 0/10= 0

the line belongs to a horizontal line, so the slope is 0

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3 years ago
What happens to the equation when y = x becomes y = -x?
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analyze the importance of compromise in government by examining and explaining The Great Compromise and The Three Fifths Comprom
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<span>Three Fifths Compromise: </span>

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8 0
3 years ago
A path 5m wide is to be built along the border and inside a square garden of side 90m. Find the cost of cementing the path at th
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Answer:

Total cost of cementing the path = Rs. 17,000.

Step-by-step explanation:

Let the square garden be PQRS

Let the region inside the garden (PQRS) be KLMN.

<u>Given the following data;</u>

Length of sides of PQRS = 90m

Width of path = 5m

Cost = Rs. 10 per m²

Area of PQRS = 90 * 90

Area of PQRS = 8100m²

<em>To find the area of KLMN;</em>

KL = KN = 90 - (5 + 5)

KL = KN = 90 - 10

KL = KN = 80m

Area of KLMN = KL * KN

Substituting into the equation, we have;

Area of KLMN = 80 * 80

Area of KLMN = 6400 m²

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Area of path = 8100 - 6400

Area of path = 1700 m²

Total cost of cementing the path = Area of path * Cost

Total cost of cementing the path = 1700 * 10

<em>Total cost of cementing the path = Rs. 17,000</em>

8 0
2 years ago
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Answer:

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Step-by-step explanation:

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