I'm assuming for g(x) you mean g(x) = x^2+3 for
.
Going with that...
![\begin{aligned}f(g(x)) &= f\left( x^2+3 \right)~~~~~\text{plug $x^2+3$ in for $x$ in $f(x)$}\\[0.5em]&= 2\cdot ( x^2+3 )~~~~~\text{so $2x$ became $2(x^2+3)$}\\[0.5em]&= 2x^2+6\endaligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Df%28g%28x%29%29%20%26%3D%20f%5Cleft%28%20x%5E2%2B3%20%5Cright%29~~~~~%5Ctext%7Bplug%20%24x%5E2%2B3%24%20in%20for%20%24x%24%20in%20%24f%28x%29%24%7D%5C%5C%5B0.5em%5D%26%3D%202%5Ccdot%20%28%20x%5E2%2B3%20%29~~~~~%5Ctext%7Bso%20%242x%24%20became%20%242%28x%5E2%2B3%29%24%7D%5C%5C%5B0.5em%5D%26%3D%202x%5E2%2B6%5Cendaligned%7D)
Just treat the enter g(x) function as a single input for f(x).
5 is you median
4 is your mean
For this case, what you must do is add the area of each of the triangles to find the total area of the polygon.
We have then:
A = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2
A = 16
Equivalently, as the area of each triangle is the same, then:
A = 2 * (8)
A = 16
Answer:
the area of the polygon is:
16
Option 3
Answer:
C: People who came to California looking for gold in 1849.
Step-by-step explanation: