The solutions to f(x) = 64 is x = 7 and x = –7.
Solution:
Given data:
– – – – (1)
– – – – (2)
To find the solutions to f(x) = 64.
Equate equation (1) and (2), we get

Subtract 15 from both sides of the equation.



Taking square root on both sides of the equation, we get
x = ±7
The solutions to f(x) = 64 is x = 7 and x = –7.
Given the radius, circumference can be solved by the equation, C = 2πr. The circumference of the circle above is C = 2π(8 in) = 16<span>π in. To solve for the length of the segment joining the arc is the circumference times the ratio of central angle and 360 degrees.
Length of the segment = (16</span>π in)(60/360) = 8/3 <span>π in
Thus, the length of the segment is approximately 8.36 in. </span>
I^22 equals to -1 since i^2 is negative one