Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
Total flowers sold = 200
Flowers are :
Carnations, Roses, and Gerber daisies
Carnations = c
Roses = r
Daisies = d
20 fewer roses than daisies ; r = d - 20
Total sales = $453
c = $1.50 each ; r = 3.75 each ; d = 2.25 each
c + d + d - 20 = 200
c + 2d = 220 - - (1)
1.50c + (d - 20)(3.75) + 2.25d = 453
1.50c + 3.75d - 75 + 2.25d = 453
1.50c + 6d = 528 - - - (2)
From (1)
c = 220 - 2d
1.5(220 - 2d) + 6d = 528
330 - 3d + 6d = 528
330 + 3d = 528
3d = 528 - 330
d = 198/3
d = 66
66 × 2.25 = $148.5
c = 220 - 2(66)
c = 88
88 * 1.50 = $132
r = d - 20
r = 66 - 20
r = 46
46 × $3.75 = $172.5
I will suppose that your queation is 10<x<y<14
there are only two odd between 10 and 14
which are 11 and 13
since x is smaller than y
x=11 and y=13
there sum will be x+y=11+13=24
