Answer:
1255.4L
Explanation:
Given parameters:
P₁ = 928kpa
T₁ = 129°C
V₁ = 569L
P₂ = 319kpa
T₂ = 32°C
Unknown:
V₂ = ?
Solution:
The combined gas law application to this problem can help us solve it. It is mathematically expressed as;
P, V and T are pressure, volume and temperature
where 1 and 2 are initial and final states.
Now,
take the units to the appropriate ones;
kpa to atm, °C to K
P₂ = 319kpa in atm gives 3.15atm
P₁ = 928kpa gives 9.16atm
T₂ = 32°C gives 273 + 32 = 305K
T₁ = 129°C gives 129 + 273 = 402K
Input the values in the equation and solve for V₂;
V₂ = 1255.4L
Answer:
The process or result of oxidizing or being oxidized.(Rust)
Explanation:
Pluto
The Ka of the solution is 8.1 * 10^-9.
<h3>What is the pH?</h3>
The pH of a solution is the concentration of hydrogen ions in the solution.
Number of moles of the acid = 26.816g/153.483g/mol = 0.175 moles
Concentration of the acid = 0.175 moles/0.5 L = 0.35 M
Now we know that the acid reacts with water as follows;
HA(aq) + H2O(l) ------> H3O^+(aq) + A^-(aq)
[H3O^+] = Antilog (-4.274)
[H3O^+] = 5.32 * 10^-5 M
Since;
[H3O^+] = [A^-] = x
Ka = x^2/[HA]
Ka = (5.32 * 10^-5)^2/( 0.35)
Ka = 8.1 * 10^-9
Hence, the Ka of the solution is 8.1 * 10^-9.
Learn more about Ka:brainly.com/question/16035742
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