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galben [10]
3 years ago
6

Which statement describes the relative masses of two different particles?

Chemistry
1 answer:
garik1379 [7]3 years ago
3 0
The answer is 2. Beta particle is high energy electrons which is the same mass as positron with little mass. Alpha particle consists of 2 neutrons and 2 protons. Neutrons and protons have almost same mass which is much larger than electrons.
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What would happen to an EM wave that never came into contact with matter?
anygoal [31]

If it was propogating through completely free space, it would be completely lossless and would therefore continue without change for infinity.

6 0
3 years ago
Weight is constant every place in the universe <br> true or false
Savatey [412]
That is false. Weight is not constant every place in the universe. Take space for example. It all depends on gravity. So, the answer is false. 
6 0
3 years ago
Read 2 more answers
What would be the best way to measure the volume of a small ?​
WITCHER [35]
You can use a graduated cylinder.
6 0
3 years ago
A student dissolves 10.7 g of lithium chloride (LiCl) in 300. g of water in a well-insulated open cup. He then observes the temp
Novosadov [1.4K]

Answer:

1) Exothermic.

2) Q_{rxn}=-8580J

3) \Delta _rH=-121.0kJ/mol

Explanation:

Hello there!

1) In this case, for these calorimetry problems, we can realize that since the temperature increases the reaction is exothermic because it is releasing heat to solution, that is why the temperature goes from 22.0 °C to 28.6 °C.

2) Now, for the total heat released by the reaction, we first need to assume that all of it is absorbed by the solution since it is possible to assume that the calorimeter is perfectly isolated. In such a way, it is also valid to assume that the specific heat of the solution is 4.184 J/(g°C) as it is mostly water, therefore, the heat released by the reaction is:

Q_{rxn}=-m_{Total}C(T_2-T_1)\\\\Q_{rxn}=-(300g+10.7g)*4.184 \frac{J}{g\°C} (28.6\°C-22.0\°C)\\\\Q_{rxn}=-8580J

3) Finally, since the enthalpy of reaction is calculated by dividing the heat released by the reaction over the moles of the solute, in this case LiCl, we proceed as follows:

\Delta _rH=\frac{Q_{rxn}}{n_{LiCl}} \\\\\Delta _rH=\frac{-8580J}{10.7g*\frac{1mol}{150.91g} }*\frac{1kJ}{1000J}  \\\\\Delta _rH=-121.0kJ/mol

Best regards!

8 0
3 years ago
Convert 26.02 x 1023 molecules of C2H8 to grams. Round your answer to the hundredths place.
aliina [53]

Answer:

x= 138.24 g

Explanation:

We use the avogradro's number

6.023 x 10^23 molecules -> 1 mol C2H8

26.02 x 10^23 molecules -> x

x= (26.02 x 10^23 molecules  * 1 mol C2H8 )/6.023 x 10^23 molecules

x= 4.32 mol C2H8

1 mol C2H8     -> 32 g

4.32 mol C2H8 -> x

x= (4.32 mol C2H8 * 32 g)/ 1 mol C2H8

x= 138.24 g

4 0
4 years ago
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