Answer:
c = 20 ft
Step-by-step explanation:
The largest square will be 14 sqrt(2) ft long
To figure out the side length of the square
use the pythagorean theorem
a^2 + b^2 =c^2
we are limited by the shortest side of the rectangle
28 ft
each side of the triangle is 1/2 the length of the short side of the rectangle or 14 ft
a^2 + b^2 =c^2
14^2 + 14^2 = c^2 where c is the side of the square
196 + 196 = c^2
392 = c^2
take the square root of each side
sqrt(392) = sqrt(c^2)
c = 14sqrt(2)
c = 19.799ft
to the nearest whole number
c = 20 ft
So first what we do is we need to get the excluded values. So to get them we have: 8x^4/x^3+7x^4.
Lets factor out the second part. x^3+7x^4 = (x^(3/4)+7x))^4
So then we get 8x^4/(x^(3/4)+7x)^4
8x^4/(x^(3/4)+7x)^4
Answer:
is the number 4
so 13/16 3/16
Step-by-step explanation:
Since we need a point that divides K-->J into two segments in a 1:3 ratio, let's flip it to a 3:1 ratio in the J-->K direction. That means that this point is 3/(3+1) = 3/4 of the way up line JK.
Let's take 3/4 of the x of K (plus the 1 for the x of J):
3/4×(9 - 1) + 1 (because the beginning ofvthe line, at J, has an x of 1)...
3/4×(8) + 1 = 6 + 1 = 7
Therefore the answer is C) 7
