Answer:
The radius of circle B is 6 times greater than the radius of circle A
The area of circle B is 36 times greater than the area of circle A
Step-by-step explanation:
we have
<em>Circle A</em>

The radius of circle A is
-----> the radius is half the diameter
<em>Circle B</em>

Compare the radius of both circles


The radius of circle B is six times greater than the radius of circle A
Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared
All circles are similar
In this problem the scale factor is 6
so

therefore
The area of circle B is 36 times greater than the area of circle A
Answer:
7627.36
Step-by-step explanation:
95342 * 8% = 7627.36
Step-by-step explanation:
since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

So probabaility for
is

So expected frequency for
is
(or
.
Answer: a^-4
Step-by-step explanation:
= a^-4
Answer:
The answer is {D}
Step-by-step explanation: