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2 years ago

Please help!

2 answers:

6 0

Let us assume the total amount of meal charge paid by Michael without tax = x
Then
Amount paid to the waiter by Michael = 15x/100
Sales tax paid by Michael = 5x/100
Now we get the equation as
x + (5x/100) + (15x/100) = 18
(100x + 5x + 15x)/100 = 18
120x/100 = 18
120x = 1800
x = 1800/120
= 180/12
= 15 dollars
So the amount paid by Michael for the meal before tax and tip is $15. I hope the procedure is clear enough for you to understand.

pishuonlain [190]2 years ago

5 0

Answer:

$15

Step-by-step explanation:

The final answer will be fifteen dollars.

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Given two independent random samples with the following results: n1=8x‾1=186s1=33 n2=7x‾2=171s2=23 Use this data to find the 90%

KonstantinChe [14]

Answer:

The point of estimate for the true difference would be:

$186-171= 15$

And the confidence interval is given by:

$(186-171) -1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= -10.753$

$(186-171) +1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= 40.753$

Step-by-step explanation:

For this case we have the following info given:

$\bar X_1 = 186$ the sample mean for the first sample

$\bar X_2 = 171$ the sample mean for the second sample

$s_1 =33$ the sample deviation for the first sample

$s_2 =23$ the sample deviation for the second sample

$n_1 = 8$ the sample size for the first group

$n_2 = 7$ the sample size for the second group

The confidence interval for the true difference is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

We can find the degrees of freedom are given:

$df = n_1 +n_2 -2 =8+7-2= 13$

The confidence level is given by 90% so then the significance would be $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ we can find the critical value with the degrees of freedom given and we got:

$t_{\alpha/2}= \pm 1.77$

The point of estimate for the true difference would be:

$186-171= 15$

And replacing into the formula for the confidence interval we got:

$(186-171) -1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= -10.753$

$(186-171) +1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= 40.753$

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2 years ago