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3 years ago

Drag each expression to match its equivalent expression. Each expression may be used only once.

Mathematics

1 answer:

ryzh [129]3 years ago

8 0

Answer:

here it is in order

x^2 = 1 / x ^ -2

x^4 ÷ x^3 = x

(x^2)^2 = x^4

x^3 × x^3 × x^3 = x ^ 9

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PLS HELP NEED THIS ASAP

lisabon 2012 [21]

Step-by-step explanation:

The equations that could be used to determine the number of chicken wings and sliders in the combination meal is:

75w + 250s = 800

w = 2s

Where:

w = chicken wings

s = sliders

The two equations derived from the question are known as simultaneous equations. Both equations have to be solved together in order to determine the number of wings and sliders.

The total calories of wings = number of wings x calories of each wing

75 x w = 75w

The total calories of sliders = number of sliders x calories of each sliders

250 x s = 250s

8 0

2 years ago

In a volleyball game, Caroline served the ball over the net 16 out of 20 times. What percent did she not make her serve over the

brilliants [131]

16/20. We reduce that and get 4/5.

After this it's much simpler to chage it.

100 dividied by 5 is 20. (20,40,60,80,100)

So the 4th number (4/100)

is 80. 80%.

20% she didn't and 80% she did :) (100-80)

7 0

3 years ago

Read 2 more answers

What is the value of 2×[34−5×(3+1)] ?

spayn [35]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{28}}}}}$

Step-by-step explanation:

Use BODMAS rule :

Bracket , Of , Division , Multiplication , Addition , Subtraction

$\sf{2 \times [ 34 - 5 \times (3 + 1) ] }$

Add the numbers : 3 and 1

$\dashrightarrow{ \sf{2 \times [ 34 - 5 \times 4 ] }}$

Multiply the numbers : 5 and 4

$\dashrightarrow{ \sf{2 \times [ 34 - 20 \: ] }}$

Subtract 20 from 34

$\dashrightarrow{ \sf{2 \times 14}}$

Multiply the numbers : 2 and 14

$\dashrightarrow{ \sf{28}}$

Hope I helped!

Best regards! :D

4 0

3 years ago

The fish population of a lake is decreasing each year. A study is conducted. But, unfortunately some data was lost. The research

Solnce55 [7]

Answer:

$F(t) = 18000(0.6666)^{t}$

Step-by-step explanation:

The fish population after t years can be modeled by the following equation:

$F(t) = F(0)(1-r)^{t}$

In which F(0) is the initial population and r is the constant rate of decay.

Year one the fish population was 18000

This means that $F(0) = 18000$

In year three the fish population was 8000 fish.

Two years later, so $F(2) = 8000$

$F(t) = F(0)(1-r)^{t}$

$8000 = 18000(1-r)^{2}$

$(1-r)^{2} = 0.4444$

$\sqrt{(1-r)^{2}} = \sqrt{0.4444}$

$1 - r = 0.6666$

$r = 0.3334$

$F(t) = 18000(0.6666)^{t}$

4 0

3 years ago

Substitute the original value of x to check that the equation is correct. x = 4 or f(x)= ?

hichkok12 [17]

Answer:

f(4)

Step-by-step explanation:

7 0

3 years ago