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2 years ago

Rewrite the expression 2-bx2<56 to get the variable b alone on one side of the equation.

Mathematics

2 answers:

Lady_Fox [76]2 years ago

7 0

Answer:

b >-54/x^2

Step-by-step explanation:

2-bx^2<56

Subtract 2 from each side

2-2-bx^2<56-2

-bx^2 <54

Divide by -1, remembering to flip the inequality

bx^2 > -54

Divide each side by x^2

bx^2/x^2 > -54/x^2

b >-54/x^2

Svetlanka [38]2 years ago

3 0

Answer:

b > -54/x²

Step-by-step explanation:

2 - bx² < 56

2 - 56 < bx²

-54 < bx²

-54/x² < b

b > -54/x²

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Answer:

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Step-by-step explanation:

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The formula for the period is:

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$y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)$

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