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3 years ago

I need help lol with this problem pls help pls pls pls

Mathematics

1 answer:

Virty [35]3 years ago

5 0

Answer:

Step-by-step explanation:

For this triangle, since the angle is included between 2 given sides, the formula will be:

$A =\frac{1}{2}ab*ac*sin(angleA)$

Putting values where they belong:

$A=\frac{1}{2}(10)(12)sin72$

Do all that in your calculator (in degree mode, NOT radian!) to get

A = 57.1 square cm

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Recall that a 6-bit string is a bit strings of length 6, and a bit string of weight 3, say, is one with exactly three 1's. How m

strojnjashka [21]

Answer:

1.. Total number of 6 bit strings is 64

2. Number of 6-bit strings with weight of 0 is 1

3. Number of 6-bit strings with weight of 1 is 6

4. Number of 6-bit strings with weight of 3 is 20

5. Number of 6-bit strings with weight of 5 is 6

6. Number of 6-bit strings with weight of 6 is 1

7. Number of 6-bit strings with weight of 7 is 0

Step-by-step explanation:

A bit string is a string that contains 0 and 1 only

1. Total number of 6 bit strings is 2^6 = 64

2. Number of 6 bit strings with weight 0 is 1

Explanation

Weight 0 means a string with no occurrence of 1

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 0 i.e. no occurrence of 1

6C0 = 6!/(6-0)!0!

6C0 = 6!/6!0!

6C0 = 1

Hence, the number of string with weight 0 (i.e. no occurrence of 1 ) is 1

3. Number of string with weight 1 is 6

Explanation

Weight 0 means a string with exactly 1 occurrence of '1'

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 1

6C1 = 6!/(6-1)!1!

6C1 = 6!/5!1!

6C1 = 6

Hence, the number of string with weight 6

4. Number of string with weight 3 is 20

Explanation

n = 6 and r = 3

6C3 = 6!/(6-3)!3!

6C3 = 6!/3!3!

6C3 = 20

Hence, the number of string with weight 3 is 20

5. Number of string with weight 5 is 6

Explanation

n = 6 and r = 5

6C5 = 6!/(6-5)!5!

6C5 = 6!/1!5!

6C5 = 6

Hence, the number of string with weight 5 is 6

6. Number of string with weight 6 is 1

Explanation

n = 6 and r = 6

6C6 = 6!/(6-6)!6!

6C6 = 6!/0!6!

6C6 = 1

Hence, the number of string with weight 6 is 1

7. Number of string with weight 7 is 0

Weight of 7 means that a string that has 7 occurrence of 1

The total length of a 6 bit is 6

Since 6 is less than 7, there's no way a bit of weight 7 can occur.

So, the right answer for this is 0.

8 0

3 years ago

F(x) = (4x–5)/6 <br> Find the Inverse

noname [10]

Answer:

F^-1 (x) = 3x/2+5/4

Step-by-step explanation:

First, replace f(x) with y

Replace every x with a y and replace every y with an x .

Solve the equation from Step 2 for y

Replace y with f−1(x) f − 1 ( x )

Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.

Hope this helps! Stay Safe!

3 0

3 years ago

Looking for a step by step explanation for this question! I take the Math QRAS Accuplacer soon and practicing my math skills but

Liula [17]

The answer is 56 cookies because i did math in my head

6 0

2 years ago

Please help! I don't know what the reasons would be for statements 3 and 4

bezimeni [28]

3 = AIA ( Alternate Interior Angles)
4 = Definition of AIA

6 0

3 years ago

There are 45 new houses being built in a neighborhood. Last month, 1/3 of them were sold. This month, 1/5 of the remaining house

Makovka662 [10]

45 new houses.....last month 1/3 were sold....
1/3(45) = 45/3 = 15 houses sold last month

this month, 1/5 of the remaining houses were sold...
remaining houses left are (45 - 15) = 30
1/5(30) = 30/5 = 6 houses sold this month

houses left : 45 - 15 - 6 = 45 - 21 = 24 houses remain <==

8 0

3 years ago