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Whitepunk [10]
3 years ago
7

John, Rasheed, and Jeorge are different ages. Rasheed is six less than twice John’s age. Jeorge’s age is nine more than half of

John’s age. The difference between Rasheed and Jeorge’s ages is no more than nine years.1.  Write an expression that represents the difference between Rasheed and Jeorge’s ages.2. Write an absolute value inequality to represent the maximum difference in their ages.3. Determine whether it is possible for John to be twenty years old. Explain your reasoning.4. Algebraically determine the greatest and least age John can be so that the difference between Rasheed and Jeorge’s ages is no more than nine years
Mathematics
1 answer:
coldgirl [10]3 years ago
6 0

Answer: 1) (2x+6)-(\dfrac{x}{2}-9), 2) x 3) No, he should be less than 16 years.

Step-by-step explanation:

Let the age of John be 'x'.

Let the age of Rasheed would be

2x-6

Let the age of Jeorge would be

\dfrac{x}{2}+9

Difference between Rasheed and Jeorge's age is more than nine years.

2x-6-(\dfrac{x}{2}+9)

1) (2x+6)-(\dfrac{x}{2}-9), 2) x 3) No, he should be less than 16 years.

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Ratio Question;
SashulF [63]

*Given

Money of Phoebe            - 3 times as much as Andy

Money of Andy                - 2 times as much as Polly

Total money of Phoebe,  - £270

   Andy and Polly

*Solution

Let

B - Phoebe's money

A - Andy's money

L - Polly's money

1. The money of the Phoebe, Andy, and Polly, when added together would total £270. Thus,

                 B + A + L  = £270                     (EQUATION 1)

2. Phoebe has three times as much money as Andy and this is expressed as

 

                 B = 3A

3. Andy has twice as much money as Polly and this is expressed as

                 A = 2L                           (EQUATION 2)

4. This means that Phoebe has ____ as much money as Polly,

                B = 3A

                B = 3 x (2L)

                B = 6L                            (EQUATION 3)

This step allows us to eliminate the variables B and A in EQUATION 1 by expressing the equation in terms of Polly's money only.

5. Substituting B with 6L, and A with 2L, EQUATION 1 becomes,

                 6L + 2L + L = £270

                               9L = £270

                                 L = £30

So, Polly has £30.

6. Substituting L into EQUATIONS 2 and 3 would give us the values for Andy's money and Phoebe's money, respectively.

                 A = 2L                          

                 A = 2(£30)

                 A = £60

Andy has £60

                 B = 6L                        

                 B = 6(£30)

                 B = £180

Phoebe has £180

Therefore, Polly's money is £30, Andy's is £60, and Phoebe's is £180.

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