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Novay_Z [31]
3 years ago
11

What is the inverse of the function below? f(x) = 2^x + 6

Mathematics
2 answers:
erik [133]3 years ago
7 0

Answer:

f^-1 (x) = log 2 (x-6)

Step-by-step explanation:

Helen [10]3 years ago
6 0

The inverse of this function would be f(x) = \frac{Log(x - 6)}{Log2}.



You can find the value of any inverse function by switching the f(x) and the x value. Then you can solve for the new f(x) value. The end result will be your new inverse function. The step-by-step process is below.



f(x) = 2^{x} - 6 ----> Switch f(x) and x



x = 2^{f(x)} - 6 ----> Add 6 to both sides



x + 6 = 2^{f(x)} -----> Take the logarithm of both sides in order to get the f(x) out of the exponent



Log(x + 6) = f(x)Log2 ----> Now divide both sides by Log2



\frac{Log(x + 6)}{Log2} = f(x) ----> And switch the order for formatting purposes.



f(x) = \frac{Log(x + 6)}{Log2}



And that would be your new inverse function.

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mojhsa [17]
I found the choices that should have been included in this problem.
a) (1.5,26)
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c) (5.5,88)
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y = 16x
choice a. y = 16(1.5) = 24
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3 years ago
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GrogVix [38]

Answer:

a=49.5 -1.28*15=30.3

So the value of height that separates the bottom 10% of data from the top 90% is 30.3.  

If the score is lower than 30.3 we consider this score as risk averse

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

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X \sim N(49.5,15)  

Where \mu=49.5 and \sigma=15

We are interested in the bottom 10% of the data.

For this part we want to find a value a, such that we satisfy this condition:

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P(X   (b)

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P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-1.28

And if we solve for a we got

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If the score is lower than 30.3 we consider this score as risk averse

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Im srry if its wrong, but my older sister says that its A and C

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