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Zarrin [17]
3 years ago
13

Pls answer this question I give brainliest thank you! Number 2

Mathematics
2 answers:
zzz [600]3 years ago
8 0

Answer:

Step-by-step explanation:

Contact [7]3 years ago
7 0

Answer:

D. 625

Step-by-step explanation:

If the side length for each block is 2 1/2 then two blocks together make 5 so 4 blocks going up makes the height 10 and two blocks for the width make 5 and the 5 blocks on the bottom going across for length make 12 1/2 and 5*10*12 1/2= 625

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Solve the compound inequality for x and identify the graph of its solution. x + 7 < 3 or x - 52 -1 O A. Solution: x < -4 o
aleksley [76]

Answer:

  D.  x < -4 or x ≥ 4

Step-by-step explanation:

You can eliminate choices A and B because the graph and the inequalities do not agree.

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You can eliminate choice C because the first inequality tells you ...

  x < some value

That means the shading will be to the left of an open circle.

This is only shown in Choice D.

_____

<em>Additional comment</em>

You can work multiple choice questions several different ways. I like to choose the simplest, which often means you do not actually need to work the problem. You only need to be able to identify ...

  • answers that are self-consistent
  • answers that are consistent with problem requirements
  • answers that are consistent with numerical and geometric facts

Here, we can eliminate incorrect answers by throwing out those that are not self-consistent and that are not consistent with the problem statement.

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If we were to solve the inequalities, we would subtract 7 from both sides of the first one:

  x +7 < 3

  x < -4 . . . . . . subtract 7 from both sides

and we would add 5 to both sides of the second one:

  x -5 ≥ -1

  x ≥ 4 . . . . . . add 5 to both sides

If you write these inequalities so the symbols point left, you have ...

 x < -4  or  4 ≤ x

This tells you shading is "outside" the segment between -4 and 4, and that there is an open-circle at x=-4. This is consistent with the number lines of choices B and D. However, these inequalities are <em>not consistent</em> with what is written in choice B.

6 0
3 years ago
Help plz in summer school
77julia77 [94]

Answer:

try A

Step-by-step explanation:

3 0
3 years ago
Graph y = -2x + 5. Tell me the coordinates.
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7 0
4 years ago
What is the period and midline?
OverLord2011 [107]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\&#10;% function transformations for trigonometric functions&#10;\begin{array}{rllll}&#10;% left side templates&#10;f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;&#10;\end{array}\qquad

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks}\\&#10;\quad \textit{horizontally by amplitude } |{{  A}}|\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\&#10;\bullet \textit{vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\&#10;&#10;&#10;\end{array}

\bf \begin{array}{llll}&#10;\bullet \textit{function period}\\&#10;\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\&#10;\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)&#10;\end{array}&#10;

so if you notice yours \bf \begin{array}{llll}&#10;3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\&#10;&\ \uparrow&\uparrow \\&#10;&B&D &#10;\end{array}

now.. normally the function \bf 3.2cos&\left( \frac{5}{3}\theta \right)
 has a D value of 0, or no vertical shift, and the amplitude and the period simply make the wave taller and thinner, but the midline is still the x-axis

now, with D = 6.1, that moves the midline  up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is 2\pi
so, the new period will be \bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

6 0
3 years ago
Which set of ordered pairs represents a function?
Katen [24]
Answer: A)
The first one because the x don’t repeat
3 0
4 years ago
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