Answer:
The area of the associated sector is 
Step-by-step explanation:
step 1
Find the radius of the circle
we know that
The circumference of a circle is equal to
we have
substitute and solve for r
step 2
Find the area of the circle
we know that
The area of the circle is equal to
we have
substitute
step 3
Find the area of the associated sector
we know that
subtends the complete circle of area 
so
by proportion
Find the area of a sector with a central angle of 
First, let's re-arrange to slope-intercept form.
x + 8y = 27
Subtract 'x' to both sides:
8y = -x + 27
Divide 8 to both sides:
y = -1/8x + 3.375
So the slope of this line is -1/8, to find the slope that is perpendicular to this, we multiply it by -1 and flip it. -1/8 * -1 = 1/8, flipping it will give us 8/1 or 8.
So the slope of the perpendicular line will be 8.
Now we can plug this into point-slope form along with the point given.
y - y1 = m(x - x1)
y - 5 = 8(x + 5)
y - 5 = 8x + 40
y = 8x + 45
Suppose U = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10} is the universal set and Q = {3, 6, 9). What is Q"?
mario62 [17]
Answer:
Step-by-step explanation:
U is the universal set, that is, a set that contains the universe of possible sets, which is formed by 10 elements in this. Q is a subset of U formed by three elements: 3, 6, 9. (
)
represents the complement of the complement of 
. The complement of is the subset of 
formed by elements not contained in . which simbolized by 
. That is, 1, 2, 4, 5, 7, 8, 10.
The complement of corresponds to the elements contained in . Hence, the correct answer is .
