The prallelogram whose adjacent sides are equal and one vertex angle is 90 degrees is a square.
The value of angle 1 is 90 degrees as the diagonal of the square intersect at 90 degrees.

The value of y is 23.
The diagonal of the square bisect the vertex angle hence the angle of 3x is 45 degrees.

Thus, the value of x is 15 degrees.
The value of 12z is 45 degrees.

Thus, the required value of z is 3.75 degrees.
They would be 69 and 70.
Your equation would be x + (x + 1) = 139
X would be the first integer and x + 1 would be the second
You would then solve the equation to get x as 69
X + 1 would then be 70
Answer:
4/6
Step-by-step explanation: