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kolbaska11 [484]
2 years ago
9

What is the lateral surface area of this right pyramid with a square base?

Mathematics
1 answer:
Brums [2.3K]2 years ago
7 0

Answer:

The lateral surface area of a square pyramid is the sum of the areas of the side faces only, whereas the surface area is the lateral area + area of the base. The lateral area of a square pyramid = 2al (or) 2a√[(a 2 /4) + h 2]. To get the surface area, we need to add the area of the base (which is a 2) to each of these formulas.The surface area of a square pyramid = a 2 + 2al (or) a 2 + 2a[(a 2 /4) + h 2]. where, a = Length of the base (square) l = slant height; h = height of the pyramid.

Step-by-step explanation:

hope this helps if not let me know have a great day :)

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Determine the average speed of the monorail, in miles per hour, over each segment of the route. Round each speed to the nearest
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3 years ago
What are the Rates of Change and the initial values to these? If you don't have the answer I'll take an explanation on how to do
gogolik [260]

Step-by-step explanation:

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4 0
3 years ago
If v = -5, what does 4v - 3 equal? (Explain aswell)
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3 years ago
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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B3%7D%20%20%3D%20%7B27%7D%5E%7B%3F%7D%20" id="TexFormula1" title=" \sqrt{3} = {27
marishachu [46]

Let the unknown be x


\sqrt{3}  = 27^x


3^\frac{1}{2}  = 3^{3x}


Both the base number are 3, so we equate the exponent:


\dfrac{1}{2}  = 3x


x = \dfrac{1}{2}  \div 3


x = \dfrac{1}{2}  \times \dfrac{1}{3}


x = \dfrac{1}{6}


Answer: 1/6


3 0
3 years ago
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