Factorizeab(ab-bc)+bc(bc-ab)

Mathematics

2 answers:

EleoNora [17]4 years ago

6 0

Answer:

(ab - bc)^2.

Step-by-step explanation:

ab(ab - bc) + bc(bc - ab)

= ab(ab - bc) - bc(ab - bc)

= (ab - bc)(ab - bc)

= (ab - bc)^2

Bond [772]4 years ago

5 0

Answer:

(ab-bc)²

Step-by-step explanation:

ab(ab-bc)+bc(bc-ab) = ⇒ distribution
(ab)² - ab*bc + (bc)² - ab*bc = ⇒ regrouping
(ab)² - 2ab*bc + (bc)² = ⇒ applying (x-y)² = x² -2xy +y² formula
(ab-bc)² ⇒ final result

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Troyanec [42]

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Let X be the time it takes for a person to choose a birthday gift, where X has an average value of 27 minutes. If the random var

jeka57 [31]

Answer:

The parameters of this exponential distribution is $\lambda$ = $\frac{1}{27}$ .

Step-by-step explanation:

We are given that the random variable X is known to be exponentially distributed and let X be the time it takes for a person to choose a birthday gift, where X has an average value of 27 minutes.

<u><em>So, X = time it takes for a person to choose a birthday gift</em></u>

The probability distribution function of exponential distribution is given by;

$f(x) = \lambda e^{-\lambda x} , x >0$ where, $\lambda$ = parameter of distribution.

Now, the mean of exponential distribution is = $\frac{1}{\lambda}$ which is given to us as average value of 27 minutes that means $\lambda = \frac{1}{27}$ .