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luda_lava [24]
3 years ago
11

Factorize​ab(ab-bc)+bc(bc-ab)​

Mathematics
2 answers:
EleoNora [17]3 years ago
6 0

Answer:

(ab - bc)^2.

Step-by-step explanation:

ab(ab - bc) + bc(bc - ab)​

= ab(ab - bc) - bc(ab - bc)​

= (ab - bc)(ab - bc)

= (ab - bc)^2

Bond [772]3 years ago
5 0

Answer:

(ab-bc)²

Step-by-step explanation:

  • ab(ab-bc)+bc(bc-ab)​ =                 ⇒ distribution
  • (ab)² - ab*bc + (bc)² - ab*bc =     ⇒ regrouping
  • (ab)² - 2ab*bc + (bc)² =                ⇒ applying (x-y)² = x² -2xy +y² formula
  • (ab-bc)²                                        ⇒ final result
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2 years ago
Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin
ozzi

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now put the value of t=\sin\theta in the above equation

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