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ryzh [129]
3 years ago
5

Please help me! There are two pictures, please keep that in mind, long explanations not needed..

Mathematics
1 answer:
kirill115 [55]3 years ago
4 0
For the 1st one the answer is the 4th bubble and for the 2nd one the answer is the 3rd bubble
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3 years ago
What is -2x - 10 = - 14x - 7?
jek_recluse [69]

x=4 because if you add 7 to 10 you get -2x-3=-14x then you add -2x to -14x and you get -3=-12 then you divide by -3 and -12 to get 4


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3 years ago
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Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini
Nat2105 [25]
By inspection, it's clear that the sequence must converge to \dfrac32 because

\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32

when n is arbitrarily large.

Now, for the limit as n\to\infty to be equal to \dfrac32 is to say that for any \varepsilon>0, there exists some N such that whenever n>N, it follows that

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|

From this inequality, we get

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}
\implies|2n-1|>\dfrac5{2\varepsilon}
\implies2n-1\dfrac5{2\varepsilon}
\implies n\dfrac12+\dfrac5{4\varepsilon}

As we're considering n\to\infty, we can omit the first inequality.

We can then see that choosing N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that N\in\mathbb N.
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3 years ago
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3 years ago
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Answer:

She messed up because if a bouquet costs $2.50 then 2.50 times 40 is $100 so she could have saved 20 more dollars

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3 years ago
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