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xeze [42]
3 years ago
13

(15+23)+7=15+(___+7)

Mathematics
2 answers:
konstantin123 [22]3 years ago
6 0
23 hope this helps!!
TEA [102]3 years ago
5 0
The answer is 23....

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Henry is solving the problems 475 x 3. His first step is shown below (400 x ___) + ( 70 x ___ ) + ( 5 x ___ ) What number should
lutik1710 [3]

Answer:

(400 × 3 ) + (70 × 3) + (5 × 3)

5 0
2 years ago
The length of a photograph is 3cm less than twice the width. The area is 54cm². Find the dimentions of the photograph.
AnnyKZ [126]
L=2w-3 

w(2w-3)=54

2w²- 3w-54=0

A= 2 , B= -3, C= -54

sub values into quadratic formula
 i attached picture of formula

Final answer:  you will be given 2 answers 6 and -4.5. -4.5 is rejected since a negative value cannot represent length because that just doesn't make sense.

w=6

Check:
L=2w-3
=2(6)-3
=12-3
=9
  9*6=54

Therefore the dimensions of the photograph are 6 cm by 9 cm



3 0
3 years ago
Read 2 more answers
Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (4, −5, 2) and parallel
Nataliya [291]

Answer:

Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e (x_o, y_o, z_o) and are parallel to \dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}

The parallel vector to the line i + zj+k = ai + bj + ck

Hence, the equation for the line is :

x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct

x = 4 + t

y = -5 + 2t

z = 2 + t

Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

\begin  {vmatrix} x = 4+ t   \\ \\  \dfrac{x-4}{1} = t  \begin {vmatirx} \end {vmatrix}\begin {vmatrix} y = - 5+2t  \\ \\ \dfrac{y+5}{2}  =t      \end {vmatrix}\begin {vmatrix} z =2+t  \\ \\ \dfrac{z-2}{1}  =t      \end {vmatrix}

∴

\dfrac{x-4}{1}= \dfrac{y+5}{2}=\dfrac{z-2}{1}

8 0
3 years ago
The LCM of 2 numbers is 60 and 1 of the numbers is 7 less than the other number. What are the numbers?
Phoenix [80]
Let's represent the two numbers by x and y.  Then xy=60.  The smaller number here is x=y-7.

Then (y-7)y=60, or y^2 - 7y - 60 = 0.  Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:

discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191.  Because the discriminant is positive, this equation has two real, unequal roots, which are
        -(-7) + sqrt(191)
y = -------------------------
             -2(1)

and 

        -(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
             -2(1)

Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.


Try thinking this way:  If the LCM is 60, then xy = 60.  What would happen if x=5 and y=12?  Is xy = 60?  Yes.  Is 5 seven less than 12?  Yes.






5 0
3 years ago
The sum of two consecutive even numbers is 54. Find the numbers.
Reil [10]
Hi! the numbers are 26 and 28!

26+(26+2) =54
8 0
2 years ago
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