The two equations are:
x = 5y - 18 (vertically opposite angles are equal)
x + y = 180 (Alternate angles , adjacent angles on a straight line)
x = 5y - 18 ---------------- (1)
x + y = 180 ---------------- (2)
From (2):
x + y = 180
y = 180 - x ---------------- Sub into (1)
x = 5(180 - x) - 18
x = 900 - 5x - 18
6x = 882
x = 147 ---------------- Sub into (2)
x = 147
y = 180 - 147 = 33
Answer: x = 147, y = 33
Yes, i<span>n mathematics, a </span>rational number<span> is any </span>number<span>that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.</span>
Answer:
£252.58
Step-by-step explanation:
$346 × £0.73/$1 = £252.58
Please rate!! I hope this helps!!
The answer is 6/5 as an improper fraction, or 1 1/5 as a mixed number.
Given :
- The length of a rectangle is 4m more than the width.
- The area of the rectangle is 45m²
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To Find :
- The length and width of the rectangle.
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Solution :
We know that,

So,
Let's assume the length of the rectangle as x and the width will be (x – 4).
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Now, Substituting the given values in the formula :







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Since, The length can't be negative, so the length will be 9 which is positive.
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

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