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earnstyle [38]
3 years ago
6

The circle below is centered at the point (-3,4) and had a radius of 3. What is it equation? ( top answers gets )

Mathematics
1 answer:
kobusy [5.1K]3 years ago
6 0

Answer:

( x+3) ^2 + ( y-4) ^2 = 9

Step-by-step explanation:

The equation of a circle can be written as

( x-h) ^2 + ( y-k) ^2 = r^2

Where ( h,k) is the center and r is the radius

( x--3) ^2 + ( y-4) ^2 = 3^2

( x+3) ^2 + ( y-4) ^2 = 9

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Answer:7/4 & 3

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4 years ago
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What is the equation in point−slope form of the line passing through (−3, −4) and (0, 2)?
Nana76 [90]

Answer:

y = 2x + 2

Step-by-step explanation:

To find the slope we do (Y1 - Y2)/(X1-X2) aka rise over run

So, m = (-4 - 2) / (-3 - 0)

m = 2

Now we have y = 2x +b

Notice one of our points is (0,2)

Since the x value of that point is 0, it is the y intercept.

In the slope intercept form b = y-intercept

Therefore b = 2

So, y = 2x + 2

4 0
3 years ago
"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d
melisa1 [442]
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
5 0
3 years ago
Find the slope of the line passing through (-2,5) and (9,-7)?
Marat540 [252]
Use the slope formula.
Y2 - Y1 / X2 - X1
(-7 - 5) / (9 - -2)
(-12) / (11)
So answer: slope(m) = -12/11
8 0
4 years ago
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