Question

The math club sells candy bars an d drinks during football games. • 60 candy bars and 110 drinks will sell for $265. • 120 candy bars and 90 drinks will sell for $270. How much does each candy bar sell for?

Answer 1

We can set up a system of equations to solve this. 

120b + 90d = 270
60b + 110d = 265

To cancel out b, first make the b terms equal.

60b · 2 + 110d · 2 = 265 · 2
120b + 220d = 530

Now subtract the equations.

 120b +   90d =  270
-120b + 220d =  530
---------------------------
            -130d = -260

Solve for d.

-130d/-130 = -260/-130
d = 2

Now put the value of d in one of the equations. 

60b + 110d = 265
60b + 110 · 2 = 265
60b + 220 = 265
60b + 220 - 220 = 265 - 220
60b = 45
60b/60 = 45/60
b = 0.75

Each candy bar sells for $0.75

Hope this helps! :)