Rewriting the equation as a quadratic equation equal to zero:
x^2 - x - 30 = 0
We need two numbers whose sum is -1 and whose product is -30. In this case, it would have to be 5 and -6. Therefore we can also write our equation in the factored form
(x + 5)(x - 6) = 0
Now we have a product of two expressions that is equal to zero, which means any x value that makes either (x + 5) or (x - 6) zero will make their product zero.
x + 5 = 0 => x = -5
x - 6 = 0 => x = 6
Therefore, our solutions are x = -5 and x = 6.
Answer:
I need help with this too
Step-by-step explanation:
<span>Lets say the 1st die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
2,1
2,2
Now say the 2nd die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
1,2
2,2
Now we want to count all cases where either dice showed a 2 and sum of the dice was < 5. However note above that the roll (2,2) is counted twice.
So there are three unique dice roll combinations which answer the criteria of at least one die showing 2, and sum of dice < 5:
1,2
2,1
2,2
The total number of unique outcomes for two dice is 6*6=36 .
So, the probability you are looking for is 3/36 = 1/12</span>
Answer:
Step-by-step explanation:
Since you have
+
5
y
in one equation and
−
5
y
in the other equation, you can add both equations to cancel out the y terms and solve for x.
−
6
x
+
5
x
=
−
x
5
y
−
5
y
=
0
1
+
10
=
11
therefore
−
x
=
11
multiplying both sides by -1:
x
=
−
11
plugging this back into the first equation:
−
6
(
−
11
)
+
5
y
=
1
66
+
5
y
=
1
subtracting 66 from both sides:
5
y
=
−
65
divide both sides by 5:
y
=
−
13
putting the x-values and y-values into one point gives:
(
−
11
,
−
13
)
as the solution
