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kramer
3 years ago
11

Find the value of x. If your answer is not an integer, leave it in simplest radical form. Diagram is not drawn to scale.. . (2 p

oints).
Mathematics
1 answer:
Levart [38]3 years ago
4 0
You are supposed to already know the side lengths for these triangles in the Unit Circle. You need to take the time to memorize! 

Triangles are "similar" if their angle measures are the same but their side lengths are different (they will be proportional, though). These triangles are 45°-45°-90° and 30°-60°-90°, respectively. 

45°-45°-90°: 
........./| 
..1./....| [(√2)/2] 
/____| 
[(√2)/2] 

30°-60°-90°: 
..../| 
1/..| [(√3)/2] 
/__| 
..½ 

note that the hypotenuse-length is always 1 when the triangle is inscribed in the Unit Circle. Multiplying the lengths of *every* side of a triangle by the same number creates a Similar Triangle. 
========================= 
26) you know that one angle is 45°, and that this is a right triangle (because of the square in the corner). That means the other angle must be 45° and this is a well-known 45°-45°-90° triangle. You know the OPPOSITE side is 5 units long and the HYPOTENUSE is y units long. Therefore, for *this* triangle: 
sin(45°) = OPP/HYP = 5/y 

But from the Unit Circle, we also know the irreducible proportion for the SINE of a 45° angle is: 
sin(45°) = OPP/HYP = [(√2)/2]/(1) = (√2)/2. 

we can equate sin(45°) for similar triangles: 
sin(45°) = sin(45°) 
5/y = (√2)/2 
multiply by reciprocals or identity-fractions until you get 
y = 5√2 
===================== 
27) you know that one angle is 30°, and that this is a right triangle (because of the square in the corner). That means the other angle must be 60° and this is a well-known 30°-60°-90° triangle. You know the OPPOSITE side is x units long, the ADJACENT side is 3√3 units long, and the HYPOTENUSE is y units long. You can solve for x and y by relating the TANGENT and COSINE proportions for *this* triangle...: 
tan(30°) = OPP/ADJ = x/[(√3)/3] 
cos(30°) = ADJ/HYP = [(√3)/3]/y 

...with the TANGENT and COSINE proportions for the 30°-60°-90° triangle inscribed in the Unit Circle: 
tan(30°) = {(½)/[(√3)/2]} = 1/√3 = [(√3)/3] 
cos(30°) = {[(√3)/2]/(1)} = [(√3)/2] 

Equate them: 
tan(30°) = tan(30°) 
x/[(√3)/3] = 1/√3 
multiply by reciprocals or identity-fractions until you get 
x = ⅓ 

cos(30°) = cos(30°) 
[(√3)/3]/y = [(√3)/2] 
multiply by reciprocals or identity-fractions until you get 
y = 2/3 

<span>==================== 

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
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Below is the solution: 

A(final)=16cm^2 ds/dT=6 da/dT=? 

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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

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1 year ago
Solve the equation for x and enter your answer in the box below <br> x + 14 =27
Helen [10]

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So we first want to ask ourselves what is the 14 doing to <em>x</em>. Well, we can see that it's being added to <em>x</em> so to get <em>x</em> by itself, we will do the opposite of addition which is subtraction. So we subtract 14 from both sides of the equation.

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3 0
3 years ago
Read 2 more answers
A prism, bases of which are equilateral triangles, circumscribes a sphere of radius 6. What is the volume of the prism?
koban [17]

Answer:

  1296√3 cubic units

Step-by-step explanation:

The volume of the prism will be the product of its base area and its height. Since it circumscribes a sphere with diameter 12, that is the height of the prism.

The central cross section of the sphere is a circle of radius 6, and that will be the size of the incircle of the base. That is, the base will have an altitude of 3 times that incircle radius, and an edge length of 2√3 times that incircle radius. Hence the area of the triangular base is ...

  B = (1/2)(6×2√3)(6×3) = 108√3 . . . . . square units

The volume of the prism is then ...

  V = Bh = (108√3)(12) = 1296√3 . . . cubic units

_____

<em>Comment on the geometry</em>

The centroid of an equilateral triangle is also the incenter and the circumcenter. The distance of that center from any edge of the triangle is 1/3 the height of the triangle. So, for an inradius of 6, the triangle height is 3×6 = 18. The side length of an equilateral triangle is 2/√3 times the altitude, so is 12√3 units for this triangle.

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4 years ago
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