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2 years ago

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What is the missing value in this table (assume a constant rate)

1 answer:

MrMuchimi2 years ago

7 0

The answer should be B.

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Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 97 + 2.19 = 99.19 = 99.2$ cm

So

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0

3 years ago

The ___________ is how steep a straight line is.

Aleonysh [2.5K]

The answer is D. Slope

8 0

3 years ago

Read 2 more answers

The graph below shows the cost of pens based on the number of pens in a pack. What would be the cost of one pen?

MaRussiya [10]

The answer would be B. $1.75

5 0

3 years ago

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3. Solve the following application of a system of linear equations.

zhuklara [117]

Answer:

Equations:

$y = 14 + 9 x$ --- Cindy

$y = 10 x$ --- Ruben

Solution to equation:

Time they have the same amount: 14 minutes

Number of cards they have at that time: 140 flashcards

Step-by-step explanation:

Solving (a): Variables and what they represent

The variables to use are x and y

Where x represent the minutes and y represents the number of flashcards in x minutes

Solving (b): System of linear equation

Cindy:

$Existing\ Flashcards = 14$

$Additional = 9$ per minute

Total number of flashcards (y) in x minutes is:

$y = Existing\ Flashcards + Additional * x$

$y = 14 + 9 * x$

$y = 14 + 9 x$

Ruben:

$Rate = 10$ per minute

Total number of flashcards (y) in x minutes is:

$y = Rate * x$

$y = 10 * x$

$y = 10 x$

Solution to Equations:

Time they have the same amount.

To do this, we $equate$ $both$ expressions

i.e.

$10x = 14 + 9x$

Collect Like Terms

$10x - 9x = 14$

$x = 14$

Number of cards they have at that time.

Here, we simply substitute 14 for x in any of the equations.

$y = 10 x$

$y = 10 * 14$

$y = 140$

or

$y = 14 + 9 x$

$y = 14 + 9 * 14$

$y = 14 + 126$

$y = 140$

4 0

2 years ago

1.3 lesson help please

Airida [17]

Answer:

1. 125

2. 25

3. 40

4. 39

First question:

(15-10)^2 + (15-5)^2

parentheses first to get 5^2 + (15-5)^2

exponents next to get 25 + (15-5)^2

parentheses again 25 + 10^2

exponents again 25 + 100 = 125

Second question:

simplify the exponents (3 *3) + (4 * 4) + (2 * 2) to get 9 + 16 + 4 = 29

Third question:

simplify in the parentheses 6 1/7 - 1/7 = 6

divide 60 by 6 to get 10

multiply 10 by 4 to get 40!

Fourth question:

simplify the fractions to get 1/3 + 8/3 = 3

multiply the 3 by 13 to get 39

7 0

2 years ago

Read 2 more answers