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3 years ago

15

What is the missing value in this table (assume a constant rate)

1 answer:

MrMuchimi3 years ago

7 0

The answer should be B.

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IF SOMEONE COULD PLEASE ANSWER ANY OF THE UNANSWERED QUESTIONS I RECENTLY ADDED IT WOULD BE MUCH APPRECIATED!!!!! ASAP PLEASE!!!

Reptile [31]

Answer:

I will go look at them now and see what I can help answer.

3 0

3 years ago

Paloma can run the 100-meter dash in 16 1/5 seconds. Savannah best time is 19.8 seconds. How much faster is Paloma than Savannah

faust18 [17]

16 1/5 seconds = 16.2 seconds

19.8 - 16.2 = 3.6

Paloma is 3.6 seconds faster than Savannah in the 100-meter dash.

6 0

4 years ago

If 2x• 3x +(2•3 )x +6x= 648, find x.

klasskru [66]

Answer:

x = -1 ± √109

Step-by-step explanation:

2x • 3x + (2 • 3)x + 6x = 648

According to PEMDAS (parentheses/exponents | multiplication/division | addition/subtraction), we should solve the parentheses first.

(2 • 3) = 6

Now we have:

2x • 3x + (6)x + 6x = 648

Now let's multiply.

2x • 3x = 6x²

6 • x = 6x

Now we have.

6x² + 6x + 6x = 648

Combine like terms.

6x² + 12x = 648

Let's factor out a 6.

6(x² + 2x) = 648

Divide both sides by 6.

x² + 2x = 108

Let's use completing the square.

Our equation is in a² + bx = c form.

Divide b by 2.

2/2 = 1

Then square it.

1² = 1

Add 1 to both sides.

x² + 2x + 1 = 108 + 1

Simplify.

x² + 2x + 1 = 109

Now we want to factor the left side. A shortcut is just to use b/2.

(x + 1)² = 109

Take the square root of both sides.

x + 1 = ±√109

The square root is as simplified as possible.

Subtract 1 from both sides.

x = -1 ± √109

Hope this helps!

4 0

3 years ago

Read 2 more answers

Find all points on the curve x=4cos(t),y=4sin(t) that have the slope of 12.

Marianna [84]

Answer:

$\left (-\dfrac{4}{\sqrt{5}},\dfrac{8}{\sqrt{5}}\right )\text{ and }\left (\dfrac{4}{\sqrt{5}},-\dfrac{8}{\sqrt{5}}\right )$ .

Step-by-step explanation:

We need to find all the points on the curve x=4cos(t),y=4sin(t) that have the slope of 1/2.

$x=4cos (t)$

$\dfrac{dx}{dt}=-4sin (t)$

$y=4sin (t)$

$\dfrac{dy}{dt}=4cos (t)$

Now,

$\dfrac{dy}{dx}=\dfrac{dy}{dt}\times \dfrac{dt}{dx}$

$\dfrac{dy}{dx}=4cos (t)\times \dfrac{1}{-4sin (t)}$

$\dfrac{dy}{dx}=-\cot t$

So, slope of the curve is $-\cot t$ .

$-\cot t=\dfrac{1}{2}$

$-\tan t=2$

$\tan t=-2$ ...(1)

Using $\sec^2t=1+\tan^2t$ , we get

$\sec^2t=1+(-2)^2$

$\sec^2t=1+4$

$\sec t=\pm \sqrt{5}$

$\cos t=\pm \dfrac{1}{\sqrt{5}}$

Now,

$\sin^2t=1-cos^2t$

$\sin t=\pm \sqrt{1-\dfrac{1}{5}}$

$\sin t=\pm \sqrt{\dfrac{4}{5}}$

$\sin t=\pm \dfrac{2}{\sqrt{5}}$

It equation (1), tan(t) is negative. So, sin and cos have different signs.

If $\sin t= \dfrac{2}{\sqrt{5}}$ , then $\cos t=- \dfrac{1}{\sqrt{5}}$ .

$x=4cos (t)=-\dfrac{4}{\sqrt{5}}$

$y=4sin (t)=\dfrac{8}{\sqrt{5}}$

If $\sin t=- \dfrac{2}{\sqrt{5}}$ , then $\cos t= \dfrac{1}{\sqrt{5}}$ .

$x=4cos (t)=\dfrac{4}{\sqrt{5}}$

$y=4sin (t)=-\dfrac{8}{\sqrt{5}}$

Therefore, the two points are $\left (-\dfrac{4}{\sqrt{5}},\dfrac{8}{\sqrt{5}}\right )\text{ and }\left (\dfrac{4}{\sqrt{5}},-\dfrac{8}{\sqrt{5}}\right )$ .

5 0

3 years ago

I will give the brainliest answer! Look at the formula for the volume of a rectangular prism. How does the surface area change i

Lynna [10]

Answer:

i guess the answer should be b

Step-by-step explanation:

surface area depends on the length and width but it doesn't depend on the height of a prism

3 0

3 years ago

Read 2 more answers