“Times as fast” means you need to multiply the original speed (10^11) by how many times faster the faster processor works:
10^11 instructions/second • 10^3 faster = 10^14 instructions/second
The key is “___ times as fast”.
I think it might be D. I'm just giving an educated guess.
Log81 (9) = 1/2
The 81 is a subscript don’t know if I could type it like that so I just put it like that
3.25 repeating as a fraction is 1.25 plus 1.25 plus 1.25 that will equal 3.25.
