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2 years ago

MATH ANYONE PLEASE HELP

Mathematics

2 answers:

BartSMP [9]2 years ago

8 0

3/8 is the answer to this question

Rom4ik [11]2 years ago

7 0

I am not sure but it looks like 2 1/8 mi.

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Find the conjugate of the complex number, use division: 2+i —— 1+i

Fittoniya [83]

I assume you mean divide using the conjugate to rationalize the denominator and express the result in standard rectangular form.

$\dfrac{2+i}{1+i} = \dfrac{2+i}{1+i} \cdot \dfrac{1-i}{1-i} = \dfrac{2(1)-i^2-2i+i}{1^2+1^2} = \frac 3 2 - \frac 1 2 i$

4 0

3 years ago

Help i will give brainliest and no links or i will report

amm1812

Answer:

Step-by-step explanation:

math

3 0

2 years ago

What is the value of a, b, and c in the quadratic equation -2x^2+4x-3=0

amm1812

A = -2
b = 4
c = -3

They are the coefficients to the terms in the equation

6 0

3 years ago

Read 2 more answers

There are two twins. One twin wants to explore the planet near Proxima Centauri and leaves on a spaceship traveling at 90% of th

miskamm [114]

Answer:

4.7 years

Step-by-step explanation:

Distance of planet from Earth = 1.3 parsec

We know that 1 parsec = 3.26 light years

And a light year is the distance traveled by light in time period of 1 year.

So, Distance of planet from Earth = 1.3 $\times$ 3.26 = 4.24 light years

Given that, the person travels at a speed equal to 90% of the light speed.

To travel to the planet from Earth, Light takes 4.24 years.

To travel the distance $D$ , at a speed $s$ light takes time of 4.24 years.

To travel the distance $D$ , at a speed $0.90s$ , the person takes time:

$\dfrac{4.24}{0.90} = \bold{4.7\ years}$

So, the twin on Earth ages by 4.7 years.

7 0

2 years ago

3. Which polynomial is equal to

Nataly_w [17]

Which polynomial is equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x)?

<h3>Answer:</h3>

The polynomial equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x) is $x^3 + 2x^2 + x + 3$

<h3>Solution:</h3>

Given that two polynomials are: $(-3x^2 + 2x - 3)$ and $(x^3 - x^2 + 3x)$

We have to find the result when $(-3x^2 + 2x - 3)$ is subtracted from $(x^3 - x^2 + 3x)$

In basic arithmetic operations,

when "a" is subtracted from "b" , the result is b - a

Similarly,

When $(-3x^2 + 2x - 3)$ is subtracted from $(x^3 - x^2 + 3x)$ , the result is:

$\rightarrow (x^3 - x^2 + 3x) - (-3x^2 + 2x - 3)$

Let us solve the above expression

There are two simple rules to remember:

When you multiply a negative number by a positive number then the product is always negative.

When you multiply two negative numbers or two positive numbers then the product is always positive.

So the above expression becomes:

$\rightarrow (x^3 - x^2 + 3x) + 3x^2 -2x + 3$

Removing the brackets we get,

$\rightarrow x^3 - x^2 + 3x + 3x^2 -2x + 3$

Combining the like terms,

$\rightarrow x^3 -x^2 + 3x^2 + 3x - 2x + 3$

$\rightarrow x^3 + 2x^2 + x + 3$

Thus the resulting polynomial is found

5 0

2 years ago