Answer:
The MAD of city 2 is <u>less than</u> the MAD for city 1, which means the average monthly temperature of city 2 vary <u>less than</u> the average monthly temperatures for City 1.
Step-by-step explanation:
For comparing the mean absolute deviations of both data sets we have to calculate the mean absolute deviation for both data sets first,
So for city 1:



Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored as the deviation is the distance of value from the mean and it cannot be negative. For this purpose absolute is used)

The deviations will be added then.
So the mean absolute deviation for city 1 is 24 ..
For city 2:



Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored)

The deviations will be added then.
So the MAD for city 2 is 11.33 ..
So,
The MAD of city 2 is <u>less than</u> the MAD for city 1, which means the average monthly temperature of city 2 vary <u>less than</u> the average monthly temperatures for City 1.
Cross multiply the expression so that we can get
(1+sinx)(1-sinx) = cos^2 x
1 - sin^2 x = cos^2 x
cos^2 x + sin^2 x = 1
since
cos^2 x + sin^2 x = 1
therefore
1 = 1
the two expressions are identical in a trigonometric sense
Remember that
1m=100cm
8m=800cm
800m=80,000cm
Volume = (edge)^3
Volume = (3/4)^3
Volume = (27/64) inches^3
Done.
Answer:
<em>2 solutions</em>
Step-by-step explanation:
Given the expression
2m/2m+3 - 2m/2m-3 = 1
Find the LCM of the expression at the left hand side:
2m(2m-3)-2m(2m+3)/(2m+3)(2m-3) = 1
open the bracket
4m²-6m-4m²-6m/(4m²-9) = 1
Cross multiply
4m²-6m-4m²-6m = 4m² - 9
-12m = 4m² - 9
4m² - 9+12m = 0
4m² +12m-9 = 0
<em>Since the resulting equation is a quadratic equation, it will have 2 solutions since the degree of the equation is 2</em>