If 24 marks is 60 %, then full marks is 40
<em><u>Solution:</u></em>
Given that 24 marks is 60 %
We are asked to find the full marks
Let the full marks be "x"
So out of "x" marks, he has got 24 marks
Therefore,
60 % of full marks = 24
60 % of x = 24

Therefore, full marks is 40
<h3><u>Method 2:</u></h3>
If 60 % is 24, then we have to find what is 100 %
60 % = 24
100 % = x
This forms a proportion, So we can solve the sum by cross multiplying

Thus full marks is 40
The area of a parallelogram is given by

Now, if we consider the 9.9 inches side as the base, then the height is the one labeled with 5.5 inches.
If instead we choose the 11 inches side as the base, the height is h.
So, we can express the area in this two equivalent ways:

Solving for h, we have

Answer:
5: Permutation. 6: Combination
Step-by-step explanation:
Being that the team of Basketball players are <u>Arranging</u> who will change the water cooler, then the Answer is <u>Permutation</u>.
Mei has homework, and she's deciding which subject to do first. She has a <u>Selection</u> of choices, thus being the Answer- <u>Combination</u>.
Hope this makes sense. If you need clarification, feel free to reach back out to me.
Answer:
We are given the correlation between height and weight for adults is 0.40.
We need to find the proportion of the variability in weight that can be explained by the relationship with height.
We know that coefficient of determination or R-square measures the proportion or percent of variability in dependent variable that can be explained by the relationship with independent variable. There the coefficient of determination is given below:

Therefore, the 0.16 or 16% of the variability in weight can be explained by the relationship with height
Given a complex number in the form:
![z= \rho [\cos \theta + i \sin \theta]](https://tex.z-dn.net/?f=z%3D%20%5Crho%20%5B%5Ccos%20%5Ctheta%20%2B%20i%20%5Csin%20%5Ctheta%5D)
The nth-power of this number,

, can be calculated as follows:
- the modulus of

is equal to the nth-power of the modulus of z, while the angle of

is equal to n multiplied the angle of z, so:
![z^n = \rho^n [\cos n\theta + i \sin n\theta ]](https://tex.z-dn.net/?f=z%5En%20%3D%20%5Crho%5En%20%5B%5Ccos%20n%5Ctheta%20%2B%20i%20%5Csin%20n%5Ctheta%20%5D)
In our case, n=3, so

is equal to
![z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]](https://tex.z-dn.net/?f=z%5E3%20%3D%20%5Crho%5E3%20%5B%5Ccos%203%20%5Ctheta%20%2B%20i%20%5Csin%203%20%5Ctheta%20%5D%20%3D%20%285%5E3%29%20%5B%5Ccos%20%283%20%5Ccdot%20330%5E%7B%5Ccirc%7D%29%20%2B%20i%20%5Csin%20%283%20%5Ccdot%20330%5E%7B%5Ccirc%7D%29%20%5D)
(1)
And since

and both sine and cosine are periodic in

, (1) becomes