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tensa zangetsu [6.8K]
3 years ago
11

.0476190476 as a fraction

Mathematics
1 answer:
frozen [14]3 years ago
3 0
Step 1: <span>Rewrite the decimal number as a fraction with 1 in the denominator.
Step 2: </span>Multiply to remove 10 decimal places. Here, you multiply top and bottom by 10 to the power of 10<span> = 10000000000
Step 3: Find the GCF of 476190476 and 10000000000 </span><span>if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 4.
</span>Step 4:<span> denominator by GCF = 4,</span><span><span><span><span>476190476÷4</span><span>10000000000÷4</span></span>=<span>1190476192500000000</span></span><span><span><span>476190476÷4</span><span>10000000000÷4</span></span>=<span>1190476192500000000</span></span></span>Therefore<span><span>X=<span>119047619/2500000000</span></span><span>X=<span>1190476192500000000</span></span></span>In conclusion,<span><span>.0476190476=<span>119047619/2500000000</span></span></span>
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A=1/2ab
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Multiply 1/2 and 3/2
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RUDIKE [14]

The tiger population loses 3/5 of its size every 2.94 decades

<h3>Rate of change using differential calculus</h3>

The given equation is:

N(t)=710(\frac{8}{125} )^t

Find the derivative of the given function

\frac{dN}{dt} =710(0.064)^tln(0.064)\\\\\frac{dN}{dt} =-1951.7(0.064)^t

When the tiger loses 3/5 of its population

dN/dt = 3/5

Solve for t

\frac{3}{5} =-1951.7(0.064)^t\\\\-0.0003=(0.064)^t

Take the natural logarithm of both sides

ln(-0.0003)=t(ln0.064)\\\\-8.087=-2.75t\\\\t=\frac{-8.087}{-2.75} \\\\t=2.94

The tiger population loses 3/5 of its size every 2.94 decades

Learn more on rate of change using calculus here: brainly.com/question/96116

#SPJ1

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2 years ago
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