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djyliett [7]
3 years ago
5

PLSSSSS HELPPPPP ASAPPPP

Mathematics
2 answers:
wel3 years ago
8 0

Answer:

Im pretty sure its B

Step-by-step explanation:

garri49 [273]3 years ago
8 0
Im really sure and i think letter b
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Find the missing side. <br> Need help please.<br> Need to show how to get the answer.
Nutka1998 [239]

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8

Step-by-step explanation:

7 0
3 years ago
Which of the following expressions are equivalent to \dfrac{-10}{3}
andreyandreev [35.5K]

Answer:

B

Step-by-step explanation:

I don't know how to explain it, but I hope I got it right and that it helped you.

7 0
2 years ago
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Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
What is the length of PC?
marshall27 [118]
<span>31 trillion kilometers or 19 trillion miles.</span>
7 0
3 years ago
PLEASE I REALLY NEED YOUR HELP!
Ivenika [448]

Answer:

x = 28

m∠ACD = 68°

Step-by-step explanation:

∠BAE ≅∠DAC because they are vertical angles

∠ACD = 180 - 124 = 56°

to find 'x':   56 + 2x + (180 - 4x) = 180

236 - 2x = 180

-2x = -56

x = 28

m∠ACD = 180 - 4(28)  =  180 - 112  =  68°

7 0
3 years ago
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