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Murrr4er [49]
3 years ago
9

Find the slope of the line?

Mathematics
2 answers:
Jet001 [13]3 years ago
5 0

We can use the points (-3, 1) and (1, -2) to solve.

Slope formula: y2-y1/x2-x1

= -2-1/1-(-3)

= 2/2

= 1

Hope This helped! Good Luck!

LenKa [72]3 years ago
3 0

Answer:

-3/4

Step-by-step explanation:

Option 1

Direction of the line: Down

-Negative Slope

Rise=-3

Run=4

Rise/Run=-3/4

Option 2

Points: (1,-2) and (-3,1)

y2-y1/x2-x1= 1-(-2)/-3-1

1+2/-3-1

-3/4

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When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
2 years ago
The area of the Pacific Ocean is 63,780,000 square miles. The Atlantic Ocean is 2.27 cross times 10 to the power of 7 square mil
olganol [36]

Answer:

4.11 * 10⁷ square miles

Step-by-step explanation:

Let P = pacific ocean

A = Atlantic ocean

P = 63,780,000 = 6.38 * 10⁷

Since A is 2.27 * 10⁷ square miles smaller than the pacific ocean,

The area of A = 6.38 * 10⁷ - 2.27 * 10⁷

The area of the atlantic ocean = 4.11 * 10⁷ square miles

4 0
2 years ago
Read 2 more answers
What is the key idea of this passage ​
Luda [366]
You have to insert the passage first
7 0
3 years ago
On a certain hot summers day, 648 people use the public swimming pool. The daily prices are $1.50 for children and $2.25 for adu
ehidna [41]

Answer:

252 children and 395 adults

Step-by-step explanation:

Make a linear system of equations, where x represents the number of children and y represents the number of adults

x+y=648

1.50x+2.25y=1269

solve using substitution, so y=648-x,

then substitute this into the second equation, so you get 1.50x+2.25(648-x)=1269,

solve for x and you will get x equals the 252

then substitute this into the first equation, so you get 252+y=648

solve and you will get y=395

3 0
3 years ago
For the following exercises, find a formula for an exponential function that passes through the two points given. (0,6) and (3,7
kirill [66]

\boxed{\boxed{f(x)=6(5)^x}}

<h2>Explanation:</h2>

An exponential function is given by the following form:

y=ab^x \\ \\ Where: \\ \\ a \ is \ a \ constant \ and \ b \ is \ the \ base

Here we know two points:

(0,6) \ and \ (3,750)

\bullet \ (0,6) \\ \\ x=0, \ y=6 \\ \\ 6=ab^0 \\ \\ \boxed{a=6} \\ \\\ \\ \bullet \ (3,750) \\ \\ x=3, \ y=750 \\ \\ 750=6b^3 \\ \\ b^3=\frac{750}{6} \\ \\ b=\sqrt[3]{125} \\ \\ \boxed{b=5}

Finally, our exponential function is:

\boxed{\boxed{f(x)=6(5)^x}}

<h2>Learn more:</h2>

Behavior of functions: brainly.com/question/12891789

#LearnWithBrainly

5 0
3 years ago
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