Answer:
The answer is 142°.
Step-by-step explanation:
We know this because corresponding angles are always congruent. Thus, in the parallel lines m || n (with the transversal) a corresponding angles is exampled. Nonetheless, x would be equal to 142°.
Am I correct? >.<
Hopefully I helped! :)
First the number of possible outcomes for two events is the product of the number of outcomes for each event....in this case:
number of outcomes=2*6=12 (because you have six number and heads and tails)
Now if you wanted to list out the possible outcomes...which is tedious and useless once you can find it as a product like done above...
h1, h2, h3, h4, h5, h6, t1, t2, t3, t4, t5, t6
Answer:
a=-8
Step-by-step explanation:
38=2a+54
2a+54=38
2a+54-54=38-54
2a=-16
2a/2=-16/2
a=-8
Answer: The answer is the third figure. Attached the image.
Step-by-step explanation: Given that Zahra runs a 500-meter race at a constant speed. We are to select the correct graph from the four options that will show her distance from the finish line during the race.
We can see in graph 2, the distance covered by Zahra in metres increases at the same rate as the time increases in minutes.
But, since we are considering from the finish line, so option (#) will be right, because Zahra starts at 500 metres, decreases in the same manner as the increase of time and goes down to 0 on the positive X-axis.
Also,
Thus, the attached graph, which is the third option is the correct graph.
9514 1404 393
Explanation:
<h3>8.</h3>
An exterior angle is equal to the sum of the remote interior angles. Define ∠PQR = 2q, and ∠QPR = 2p. The purpose of this is to let us use a single character to represent the angle, instead of 4 characters.
The above relation tells us ...
∠PRS = ∠PQR +∠QPR = 2q +2p
Then ...
∠TRS = (1/2)∠PRS = (1/2)(2q +2p) = q +p
and
∠TRS = ∠TQR +∠QTR . . . . . exterior is sum of remote interior
q +p = (1/2)(2q) +∠QTR . . . . substitute for ∠TRS and ∠TQR
p = ∠QTR = 1/2(∠QPR) . . . . . subtract q
__
<h3>9.</h3>
For triangle ABC, draw line DE parallel to BC through point A. Put point D on the same side of point A that point B is on the side of the median from vertex A. Then we have congruent alternate interior angles DAB and ABC, as well as EAC and ACB. The angle sum theorem tells you that ...
∠DAB +∠BAC +∠CAE = ∠DAE . . . . a straight angle = 180°
Substituting the congruent angles, this gives ...
∠ABC +∠BAC +∠ACB = 180° . . . . . the desired relation
