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3 years ago

This 2 pls i need help with explanation sum

Mathematics

1 answer:

Nataliya [291]3 years ago

4 0

9514 1404 393

Explanation:

An exterior angle is equal to the sum of the remote interior angles. Define ∠PQR = 2q, and ∠QPR = 2p. The purpose of this is to let us use a single character to represent the angle, instead of 4 characters.

The above relation tells us ...

∠PRS = ∠PQR +∠QPR = 2q +2p

Then ...

∠TRS = (1/2)∠PRS = (1/2)(2q +2p) = q +p

and

∠TRS = ∠TQR +∠QTR . . . . . exterior is sum of remote interior

q +p = (1/2)(2q) +∠QTR . . . . substitute for ∠TRS and ∠TQR

p = ∠QTR = 1/2(∠QPR) . . . . . subtract q

For triangle ABC, draw line DE parallel to BC through point A. Put point D on the same side of point A that point B is on the side of the median from vertex A. Then we have congruent alternate interior angles DAB and ABC, as well as EAC and ACB. The angle sum theorem tells you that ...

∠DAB +∠BAC +∠CAE = ∠DAE . . . . a straight angle = 180°

Substituting the congruent angles, this gives ...

∠ABC +∠BAC +∠ACB = 180° . . . . . the desired relation

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1.explain how you would graph the inequality y<2/3x+1 on a coordinate plane. Be very specific and describe all your steps ple

xxTIMURxx [149]

Answer:

Step-by-step explanation:

1. ok so 2/3 is the rise over run for x so then 1 is the intercept so the first set of coordinates would be (-1,0) then you would use the rise over run and go up two and over three so the second set of coordinates would be (1,3) and so on

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7 0

4 years ago

What is the x value such that y=15 - 3x and y = 0

qwelly [4]

-3x+15=0
Add -15 both sides
-3x=-15
Divided by -3 both sides
x=-15/-3
x=5

3 0

3 years ago

Read 2 more answers

The radius of a right circular cone is increasing at a rate of 1.9 in/s while its height is decreasing at a rate of 2.2 in/s. At

musickatia [10]

Answer:

Volume of the cone is increasing at the rate $9916\pi \frac{in^3}{s}$ .

Step-by-step explanation:

Given: The radius of a right circular cone is increasing at a rate of $1.9$ in/s while its height is decreasing at a rate of $2.2$ in/s.

To find: The rate at which volume of the cone changing when the radius is $134$ in. and the height is $136$ in.

Solution:

We have,

$\frac{dr}{dt} =1.9 \:\text{in/s}$ , $\frac{dh}{dt}=-2.2\:\text{in/s}$ , $r=134 \:\text{in}$ , $h=136\:\text{in}$

Now, let $V$ be the volume of the cone.

So, $V=\frac{1}{3}\pi r^{2}h$

Differentiate with respect to $t$ .

$\frac{dv}{dt} =\frac{1}{3}\pi \left [ r^2\frac{dh}{dt}+h\left ( 2r \right )\frac{dr}{dt} \right ]$

Now, on substituting the values, we get

$\frac{dv}{dt} =\frac{1}{3}\pi\left [ \left ( 134 \right )^2\left ( -2.2 \right )+\left ( 136\right )\left ( 2 \right )\left ( 134 \right )\left ( 1.9 \right ) \right ]$