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3 years ago

Please help me out with this question

Mathematics

1 answer:

I am Lyosha [343]3 years ago

6 0

Answer:

no. 4

Step-by-step explanation:

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drek231 [11]

Answer:

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2 years ago

a point is chosen at random on AK. what is the probability that the point will be on CD. don't forget to reduce

Novay_Z [31]

Answer:

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3 years ago

The perimeter of a 14 ft , 8 ft rectangle

lara [203]

Answer:44 ft

Step-by-step explanation:

P=2(l+w)

P=2(14+8)

P=2(22)

P=44

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3 years ago

Read 2 more answers

Kinda is buying boxes of ice cream sandwiches for her class party. She has to decide how many boxes she should purchase

kupik [55]

Please be specific, how many people are in her class?

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3 years ago

PLEASE HELP

lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function $j\left(x\right) \ = \ 4^{x-2}$ , hence the average rate of change (slope of the blue line) between the $x$ and $x+h$ is

$\text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}$

$\\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}$

7 0

1 year ago