Say, length =x mileWidth =. x/5 milex*x/5=9/2020x*x=45x*x=45/20 =9/4x=3/2 mileLength =3/2 milesWidth=. 3/10 miles
The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.
The measurement of two of the walls is 2.86 metres and 3.16 metre
Area of the two walls = 2(length x breadth)
Area = 2(2.86 x 3.16) = 18.0752 m²
The measurement of the other two walls is 2.86 metres and 3.42 metres
Area of the two walls = 2(length × breadth)
Area = 2(2.86 × 3.42) = 19.5624 m²
Total area = 18.0752 + 19.5624 = 37.6376 m²
If one can of paint can cover 15 m², the no. of cans required to paint the bedroom will be
No. of cans = Total area/Area covered by one can of paint
No. of cans = 37.6376/15 = 2.5091 = 3 cans (approx.)
Answer:
38-15c-4
Step-by-step explanation:
38-x=12c+4+3c
38-x=15c+4
x=38-15c-4
I believe it should be 22½ or 22 books
You would need to divide 18 and ⅘
18 ÷ ⅘ = 22½
I hope this helps, even though I’m not totally sure :)
Answer: quit
Step-by-step explanation:
