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2 years ago

if the triangle on the grid below is translated by using the rule (x,y) ---> (x-2,y+2) what will be the coordinates of A'?

Mathematics

2 answers:

Black_prince [1.1K]2 years ago

7 0

A is the answer i know

Vladimir79 [104]2 years ago

6 0

Answer:

The correct option is 1. The coordinates of A' is (-4,0).

Step-by-step explanation:

From the given figure it is noticed that the coordinates of A is (-2,-2).

The translation of triangle is defined as

$(x,y)\rightarrow (x-2,y+2)$

The coordinates of A' is

$A(-2,-2)\rightarrow A'(-2-2,-2+2)$

$A(-2,-2)\rightarrow A'(-4,0)$

The coordinates of A' is (-4,0). Therefore correct option is 1.

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Aleonysh [2.5K]

Answer:

x = 0 or x = 7

Step-by-step explanation:

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3 years ago

Please help!! Select all the triangles that have an area of 8 square units in the picture. Explain how you know please?

Soloha48 [4]

Answer: A,B,D,E

Step-by-step explanation: All of them either have a base and height of 4, or if its E, it is 8 by2. The formula for solving a triangle is base x height divided by 2. In this case, the two sides have to equal 16, as the area is 16/2, or 8

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3 years ago

Need Help ASAP!!!

Hitman42 [59]

Answer:

The answer to your question is:

x = 1

y = 1

z = 0

Step-by-step explanation:

-2x + 2y + 3z = 0 (1)

-2x - y + z = -3 (2)

2x + 3y + 3z = 5 (3)

Solve (1) and (2)

Multiply 2 by 2

-2x + 2y + 3z = 0

-4x -2y + 2z = -6

-6x + 5 z = -6 (4)

Solve (2) and (3)

Multiply 2 by 3

-6x - 3y + 3z = -9

2x + 3y + 3z = 5

-4x + 6z = -4 (5)

Solve (4) and (5)

Multiply (4) by 2 and (5) by -3

-12x + 10 z = -12

12x - 18z = 12

-6z = 0

z = 0

Then

-4x + 6(0) = -4

-4x = -4

x = -4/-4

x = 1

Finally

-2(1) - y + (0) = -3

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y = 1

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3 years ago

Read 2 more answers

Postulates can be used to prove theorems. True False

nikitadnepr [17]

No, because postulates are assumptions. Some true, some not. So it can't be used to prove it

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3 years ago

Consider m = y2 - y1/ x2 - x1 . Which x1 and x2-values would determine that the line is vertical? Justify your answer

Y_Kistochka [10]

Answer:

$x_2=x_1$

Step-by-step explanation:

We were given the slope formula;

$m=\frac{y_2-y_1}{x_2-x_1}$

This line is vertical if the denominator is zero.

That is when $x_2-x-1=0$

This implies that;

$x_2=x_1$

Justification;

When $x_2=x_1$ , then, the line passes through;

$(x_1,y_1)$ and $(x_1,y_2)$

The slope now become

$m=\frac{y_2-y_1}{x_1-x_1}=\frac{y_2-y_1}{0}$

The equation of the line is

$y-y_1=\frac{y_2-y_1}{0}(x-x_1)$

This implies that;

$0(y-y_1)=(y_2-y_1)(x-x_1)$

$0=(y_2-y_1)(x-x_1)$

$\frac{0}{y_2-y_1}=(x-x_1)$

$0=(x-x_1)$

$x=x_1$ ... This is the equation of a vertical line.

3 0

2 years ago