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tamaranim1 [39]
3 years ago
11

Can someone help me out with this please and thank you

Mathematics
2 answers:
alekssr [168]3 years ago
8 0
C because -A is less than -C due to how it is positioned on the number line
anastassius [24]3 years ago
5 0

Answer:

C

Step-by-step explanation:

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What a bar or a line is placed over repeating digits the number is written by using blank
Pavlova-9 [17]
The bar or line the is placed over repeating digits in a decimal in called a vinculum
7 0
3 years ago
Which of the following proportions is true?<br> 4/16=2/14 15/20=24/36 12/15=47/50 16/36=12/27
KengaRu [80]
The correct proportion is 16/36=12/27
4 0
4 years ago
Find the domain over which the function y = x + 6x is monotonic increasing.
iragen [17]

Answer:

x > -3

\sf (-3, \infty)

Step-by-step explanation:

Domain: input values (x-values)

Monotonic increasing:  always increasing.  
A function is increasing when its graph rises from left to right.

The graph of a quadratic function is a parabola.  If the leading term is positive, the parabola opens upwards.  The domain over which the function is increasing for a parabola that opens upwards is values greater than the x-value of the vertex.

<u>Vertex</u>

Standard form of quadratic equation:  \sf y=ax^2+bx+c

\textsf{x-value of vertex}=\sf -\dfrac{b}{2a}

Given function:

\sf y=x^2+6x

Therefore, x-value of function's vertex:

\sf \implies x= -\dfrac{6}{2}=-3

<u>Final Solution</u>

The function is increasing when x > -3

\sf (-3, \infty)

4 0
3 years ago
How do you do this problem 2n^3-n^2-136n=0
Rzqust [24]
<span>2n^3-n^2-136   :Equation: 

                                      Substitute 0 for n  

</span>                                      Simplify {20}^{3}<span> to </span><span>8000 
</span>
<span>8000−<span>0<span><span>​^2</span><span>​​</span></span></span>−136 

</span>                                     Simplify <span>{0}^{2}<span>​​</span></span><span> to </span><span>0 
</span><span><span>8000−0−136 

= 7864</span></span><span>
</span>
5 0
3 years ago
Cargo ships arrive at a loading dock at a rate of 2 per day. The dock has the capability of handling 3 arrivals per day. How man
Vsevolod [243]

Answer:

4 days

Step-by-step explanation:

We need to use the probability functions of each of the intervals to know the Probability number and then use it in the expected value.

P(x>3 cargo ships) = 1-P(x<=3)

P(x>3) = 1-P(x<=3)

P(x>3) = 1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)]

P(x>3) = 1 - [\frac{e^{-2}2^0}{01}+\frac{e^{-2}2^1}{11}+\frac{e^{-2}2^2}{21}+\frac{e^{-3}2^3}{31}]

P(x>3) = 1- [0.1353(1+2+2+1.33)]

P(x>3) = 1-0.856

P(x>3) = 0.1431

Als n=30, expected number is

E(x) =30*P(x>3)

E(x) = 30*0.1431

E(x) = 4.293

I expect 4.293 or 4 days per month the block being unable to hanlde all arriving ships

6 0
3 years ago
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