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Lunna [17]
3 years ago
10

Four friends share the profit of a lawn care service equally. The friends charge $45 per lawn and spend $30 of their total earni

ngs on gasoline for the lawnmowers each week. Which inequality can be used to find m, the number of lawns they need to mow next week so that each person earns at least $275?
Mathematics
2 answers:
rusak2 [61]3 years ago
5 0

Answer:

45m - 30 ≥ 1100

Step-by-step explanation:

Amount charged for mowing a lawn = $ 45

The total number of lawns they mow in a week is "m". Since, they charge $ 45 per one lawn, for m lawns the total amount they will charge will be $ 45m

They spend $ 30 of their total earnings on gasoline each week. So the total profit accumulated each week will be = 45m - 30

Each person wants to earn atleast $275. Since, they are 4 friends in total, the total they want to earn is atleast 4 x 275 = $ 1100

We need to find how many lawns they need to mow to earn atleast $ 1100 in the next week. We can set up the equation as:

45m - 30 ≥ 1100

This inequality can be used to used to find m, the number of lawns they need to mow next week so that each person earns at least $275. This can be solved as follows:

45m ≥ 1130

m ≥ 25.11

Since the number of lawns need to be whole number, and the need atleast $ 1100, so we round up the number of lawns to 26 to ensure they earn atleast $ 1100 in total .

Therefore,

m ≥ 26

TEA [102]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
STatiana [176]

Answer:

24761 mosquitoes

5.4 days

Step-by-step explanation:

Let the equation that shows the population of the mosquitoes after x days,

A=P(1+r)^x

Where,

P = Initial population,

r = rate of increasing per day,

Here, A = 1000, when x = 0,

1000=P(1+r)^0\implies P = 1000

A = 1900 when x = 1,

1900 = P(1+r)^1\implies 1900 = 1000(1+r)\implies 1.9 = 1 + r\implies r = 0.9

Thus, the required function that represents the population after x days,

A=1900(1+0.9)^x=1900(1.9)^x

If x = 4,

The number of mosquito after 4 days,

A=1900(1.9)^4 = 24760.99\approx 24761

If A = 60,000,

60000 = 1900(1.9)^x

\frac{600}{19}=1.9^x

Taking log both sides,

\log(\frac{600}{19})=x\log 1.9

\implies x = \frac{\log(\frac{600}{19})}{\log 1.9}=5.378\approx 5.4

Thus, there will 60,000 mosquitoes after 5 days.

6 0
3 years ago
A survey of 400 non-fatal accidents showed that 189 involved the use of a cell phone. Find a point estimate for p, the populatio
nekit [7.7K]

Answer:

The point estimate for the proportion is p = 0.4725

The 95% confidence interval for the proportion of non-fatal accidents that involved the use of a cell phone is (0.4236, 0.5214).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 400

Point estimate

\pi = p = \frac{189}{400} = 0.4725

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4725 - 1.96\sqrt{\frac{0.4725*0.5275}{400}} = 0.4236

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4725 + 1.96\sqrt{\frac{0.4725*0.5275}{400}} = 0.5214

The 95% confidence interval for the proportion of non-fatal accidents that involved the use of a cell phone is (0.4236, 0.5214).

7 0
3 years ago
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