Factor
in form
ax²+bx+c form
use the ac method
1. mulitply a and c
2. factor the result such that the 2 factors add to b
3. split b into those 2 factors
4. group the terms
5. undistribute common factors
6. undistribute again
first multiply ac
4 times 5=20
now
what 2 numbers multiply to 20 and add to 12
2 and 10
4x²+2x+10x+5
group
(4x²+2x)+(10x+5)
undistribute
2x(2x+1)+5(2x+1)
undistribute the (2x+1)
(2x+1)(2x+5) is factored form whih you have there, nice
C. For every decrease of one chore completed, one hour was spent on the internet.
12x-5y=2
-5y=2-12x
y=-2/5+12/5x
should know the m=12/5
and (2,3) bring them to the line equation:
3=12/5x2+b
6/5+b=3
b=3-6/5
b=9/5
y=12/5x+9/5
Which means the answer is not in the choices.
