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zlopas [31]
2 years ago
13

Aiden buys a bag of cookies that contains 9 chocolate chip cookies, 8 peanut butter cookies, 8 sugar cookies and 9 oatmeal cooki

es. What is the probability that Aiden randomly selects an oatmeal cookie from the bag, eats it, then randomly selects a chocolate chip cookie
Mathematics
1 answer:
Airida [17]2 years ago
5 0

The probability that Aiden randomly selects an oatmeal cookie from the bag, eats it, then randomly selects a chocolate chip cookie is 0.0721

<h3>How to determine the probability?</h3>

The distribution of the cookies is given as:

  • 9 chocolate chip cookies
  • 8 peanut butter cookies
  • 8 sugar cookies
  • 9 oatmeal cookies

When he eats a cookie, the number of cookies reduces by 1

So, the required probability is:

P(Oatmeal and Chocolate) = Oatmeal/Total * Chocolate/Total - 1

This gives

P(Oatmeal and Chocolate) = 9/(9 + 8 + 8 + 9) * 9/(9 + 8 + 8 + 9 -1)

Evaluate

P(Oatmeal and Chocolate) = 0.0721

Hence, the probability is 0.0721

Read more about probability at:

brainly.com/question/25870256

#SPJ1

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A researcher would like to estimate p, the proportion of U.S. adults who support recognizing civil unions between gay or lesbian
Minchanka [31]

Answer:

Question 1:

(b) 4,445

Question 2:

(c) 2.1%

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Question 1:

We have no previous estimate for the population proportion, so we use \pi = 0.5.

The sample size is n for which M = 0.015. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.015 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.015\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.015}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.015})^2

n = 4268

Samples above this value should be used, and the smaller sample above this value is of 4445, so the answer is given by option b.

Question 2:

Now we find M for which n = 2222.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.96\sqrt{\frac{0.5*0.5}{2222}}

M = 0.021

So 2.1%, and the correct answer is given by option c.

3 0
2 years ago
First come first served <br> brainiest:) do it right
Arte-miy333 [17]

To Be Honest I Dont Know

3 0
2 years ago
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KonstantinChe [14]

Perpendicular Bisector

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8 0
3 years ago
(Multiple choice) One factor of 9x^4 - 6x^3 + 3x^2 is:
DIA [1.3K]
So it's like 'which one of the number given is a factor of, say, 10' and the choices are 4,5,7,9. the answer is 5 so just factor out the equation

the factored out form is
factor out the 3x^2 and get
(3x^2)(3x^2-2x+1)
and 3x^2-2x+1 is the fourth choice
4 0
4 years ago
The sum of three integers is 211. The sum of the first and second integer exceeds the third by 39. The third interference is 23
finlep [7]

Answer:

A= 109 B= 16 C=86

Step-by-step explanation:

Write an equation for each statement:

:

"The sum of three integers is 211."

a + b + c = 211

:

"The sum of the first an second integers exceeds the third by 39."

a + b = c + 39

a + b - c = 39

:

"The third integer is 23 less than the first."

c = a - 23:

Subtract the 2nd equation from the 1st equation

a + b + c = 211

a + b - c = 39

---------------subtraction eliminates a and b, find c

2c = 172

c = 86:

Find a using the 3rd equation

86 = a - 23

86 + 23 = a

a = 109

:

Find b using the 1st equation

109 + b +86 = 211

b = 211 - 195

b = 16

4 0
3 years ago
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