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timurjin [86]
4 years ago
7

The weight of Sean's puppy is 4 pounds more than 2 times it's weight, in pounds, of Jay's puppy. If Sean's puppy weighs 24 pound

s,what is the weight, in pounds, of Jay's puppy
Mathematics
2 answers:
Maurinko [17]4 years ago
6 0

Answer:

The weight of the Jay's puppy be 10 pounds .

Step-by-step explanation:

Let us assume that the weight, in pounds, of Jay's puppy be x.

As given

The weight of Sean's puppy is 4 pounds more than 2 times it's weight, in pounds, of Jay's puppy.

Weight of the Sean's puppy = 4 + 2x

As given

If Sean's puppy weighs 24 pounds .

4 + 2x = 24

2x = 24 - 4

2x = 20

x = \frac{20}{2}

x = 10

Therefore the weight of the Jay's puppy be 10 pounds .


diamong [38]4 years ago
3 0
S = 2j + 4
s = 24

24 = 2j + 4
24 - 4 = 2j
20 = 2j
20/2 = j
10 = j....jay's puppy is 10 lbs
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