A reasonable estimate would be 180 students with blue eyes
Ya, calculus and related rates, such fun!
everything is changing with respect to t
altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min
area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min
base=db/dt
alright
area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt
ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b
so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min
therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt
the base is decreasing at 1.6cm/min
1) (-4) + (-9) = -13
2) 5 + (-12) = -7
3) -6 + 5 = -1
4) -7 + 7 = 0
<span>5) -7 + 2 ___ 3 + (-9)
- 5 ____ - 6
</span>-7 + 2 > 3 + (-9)
6) <span>4 + (-8) ___ 6 + (-8) + (-6)
- 4 ____ - 8
</span><span>4 + (-8) > 6 + (-8) + (-6)
7) </span><span>$66
8) </span><span>-$12
</span>
Sarah needs 4.4 centimeters more to reach 5 feet before her next birthday.
Answer:
В (50°)
Step-by-step explanation:
m∠XWY=180-95=85°
x=180-(m∠XWY+m∠XYW)=180-(85+45)=50°
